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#76 2013-09-19 23:07:56

Derick Mixon
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Re: Math

Can you show me how you would solve this? I have the answers is you want to see them


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#77 2013-09-20 00:39:40

bobbym
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Re: Math



Start by doing the subtraction on the left side.



Now cross multiply.







Factor,



You have x = 0 and x = -2. We reject the 0 solution so x = -2.


In mathematics, you don't understand things. You just get used to them.
I have the result, but I do not yet know how to get it.
All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

#78 2013-09-20 01:54:28

Derick Mixon
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Re: Math

1/2 right?

#79 2013-09-20 01:58:16

bobbym
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Re: Math

For the first one?


In mathematics, you don't understand things. You just get used to them.
I have the result, but I do not yet know how to get it.
All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

#80 2013-09-20 01:59:15

Derick Mixon
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Re: Math

yes

#81 2013-09-20 02:00:42

bobbym
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Re: Math

In post #77 I solved it already, the answer is -2.


In mathematics, you don't understand things. You just get used to them.
I have the result, but I do not yet know how to get it.
All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

#82 2013-09-20 02:03:12

Derick Mixon
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Re: Math

ok youre right I see It now what abou the next one

Last edited by Derick Mixon (2013-09-20 02:04:48)

#83 2013-09-20 02:04:54

bobbym
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Re: Math

Give me some time to do the other ones. I will post them right here.


In mathematics, you don't understand things. You just get used to them.
I have the result, but I do not yet know how to get it.
All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

#84 2013-09-20 02:06:50

Derick Mixon
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Re: Math

ok thanks

#85 2013-09-20 02:40:41

bobbym
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Re: Math



Multiply both sides by 20.



Clean it up.



Add 8 to both sides.





Subtract 5x from both sides.



Divide both sides by 15 and you get x = - ( 17 / 15).


In mathematics, you don't understand things. You just get used to them.
I have the result, but I do not yet know how to get it.
All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

#86 2013-09-20 03:17:10

Derick Mixon
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Re: Math

I have that as well. ok the next question

#87 2013-09-20 07:45:36

bobbym
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Re: Math



Times both sides by 24.



Add 9 to both sides.



Subtract 8x from both sides.



x = 1


In mathematics, you don't understand things. You just get used to them.
I have the result, but I do not yet know how to get it.
All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

#88 2013-09-20 09:51:36

Derick Mixon
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Re: Math

are you done for the night?

#89 2013-09-20 12:20:39

bobbym
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Re: Math

Hi;

Yes, I am going to eat.


In mathematics, you don't understand things. You just get used to them.
I have the result, but I do not yet know how to get it.
All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

#90 2013-09-20 22:37:08

Derick Mixon
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Re: Math

Did you do the rest yet?

#91 2013-09-20 22:40:34

bobbym
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Re: Math



Take 1 / 9 away from both sides.



Flip them both,

x = 3

For the last one:



Times both sides by 15x.



Divide both sides 4.

x = ( 14 / 4 ) = ( 7 / 2 )


In mathematics, you don't understand things. You just get used to them.
I have the result, but I do not yet know how to get it.
All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

#92 2013-09-22 03:17:02

Derick Mixon
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Re: Math

Are you in today?

#93 2013-09-22 03:19:51

bobbym
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Re: Math

Yes, I am.


In mathematics, you don't understand things. You just get used to them.
I have the result, but I do not yet know how to get it.
All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

#94 2013-09-22 03:45:47

Derick Mixon
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Re: Math

State the domain of y = x2

 
State the range of y = x2

 
State the domain of y = x2 + 2

 
State the range of y = x2  + 2

 
State the domain of y = 2x2 + 3

 
State the range of y = 2x2 + 3

 
State the domain of y = x2 5

 
State the range of y = x2  - 5

 
State the domain of y = -x2

 
State the range of y = x2

#95 2013-09-22 03:54:31

Derick Mixon
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Re: Math

Can you show me how to solve them?

#96 2013-09-22 03:57:29

bobbym
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Re: Math

What is x2?


In mathematics, you don't understand things. You just get used to them.
I have the result, but I do not yet know how to get it.
All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

#97 2013-09-22 04:24:06

Derick Mixon
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Re: Math

The x value

#98 2013-09-22 04:28:58

bobbym
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Re: Math

And the 2, is that a power?


In mathematics, you don't understand things. You just get used to them.
I have the result, but I do not yet know how to get it.
All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

#99 2013-09-22 09:18:22

Derick Mixon
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Re: Math

yes

#100 2013-09-24 06:26:49

bobbym
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Re: Math

State the domain of y = x^2


State the range of y = x^2

I get the domain as R and the range as [0,∞)

State the domain of y = x^2 + 2


State the range of y = x^2  + 2

Domain is R and the range is all positive reals greater than or equal to 2.


In mathematics, you don't understand things. You just get used to them.
I have the result, but I do not yet know how to get it.
All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

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