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**Derick Mixon****Member**- Registered: 2013-09-03
- Posts: 65

Can you show me how you would solve this? I have the answers is you want to see them

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 96,590

Start by doing the subtraction on the left side.

Now cross multiply.

Factor,

You have x = 0 and x = -2. We reject the 0 solution so x = -2.

**In mathematics, you don't understand things. You just get used to them.**

**If it ain't broke, fix it until it is.**

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**Derick Mixon****Member**- Registered: 2013-09-03
- Posts: 65

1/2 right?

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 96,590

For the first one?

**In mathematics, you don't understand things. You just get used to them.**

**If it ain't broke, fix it until it is.**

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**Derick Mixon****Member**- Registered: 2013-09-03
- Posts: 65

yes

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 96,590

In post #77 I solved it already, the answer is -2.

**In mathematics, you don't understand things. You just get used to them.**

**If it ain't broke, fix it until it is.**

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**Derick Mixon****Member**- Registered: 2013-09-03
- Posts: 65

ok youre right I see It now what abou the next one

*Last edited by Derick Mixon (2013-09-19 04:04:48)*

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 96,590

Give me some time to do the other ones. I will post them right here.

**In mathematics, you don't understand things. You just get used to them.**

**If it ain't broke, fix it until it is.**

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**Derick Mixon****Member**- Registered: 2013-09-03
- Posts: 65

ok thanks

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 96,590

Multiply both sides by 20.

Clean it up.

Add 8 to both sides.

Subtract 5x from both sides.

Divide both sides by 15 and you get x = - ( 17 / 15).

**In mathematics, you don't understand things. You just get used to them.**

**If it ain't broke, fix it until it is.**

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**Derick Mixon****Member**- Registered: 2013-09-03
- Posts: 65

I have that as well. ok the next question

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 96,590

Times both sides by 24.

Add 9 to both sides.

Subtract 8x from both sides.

x = 1

**In mathematics, you don't understand things. You just get used to them.**

**If it ain't broke, fix it until it is.**

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**Derick Mixon****Member**- Registered: 2013-09-03
- Posts: 65

are you done for the night?

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 96,590

Hi;

Yes, I am going to eat.

**In mathematics, you don't understand things. You just get used to them.**

**If it ain't broke, fix it until it is.**

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**Derick Mixon****Member**- Registered: 2013-09-03
- Posts: 65

Did you do the rest yet?

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 96,590

Take 1 / 9 away from both sides.

Flip them both,

x = 3

For the last one:

Times both sides by 15x.

Divide both sides 4.

x = ( 14 / 4 ) = ( 7 / 2 )

**In mathematics, you don't understand things. You just get used to them.**

**If it ain't broke, fix it until it is.**

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**Derick Mixon****Member**- Registered: 2013-09-03
- Posts: 65

Are you in today?

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 96,590

Yes, I am.

**In mathematics, you don't understand things. You just get used to them.**

**If it ain't broke, fix it until it is.**

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**Derick Mixon****Member**- Registered: 2013-09-03
- Posts: 65

State the domain of y = x2

State the range of y = x2

State the domain of y = x2 + 2

State the range of y = x2 + 2

State the domain of y = 2x2 + 3

State the range of y = 2x2 + 3

State the domain of y = x2 5

State the range of y = x2 - 5

State the domain of y = -x2

State the range of y = x2

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**Derick Mixon****Member**- Registered: 2013-09-03
- Posts: 65

Can you show me how to solve them?

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 96,590

What is x2?

**In mathematics, you don't understand things. You just get used to them.**

**If it ain't broke, fix it until it is.**

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**Derick Mixon****Member**- Registered: 2013-09-03
- Posts: 65

The x value

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 96,590

And the 2, is that a power?

**In mathematics, you don't understand things. You just get used to them.**

**If it ain't broke, fix it until it is.**

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**Derick Mixon****Member**- Registered: 2013-09-03
- Posts: 65

yes

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 96,590

State the domain of y = x^2

State the range of y = x^2

I get the domain as R and the range as [0,∞)

State the domain of y = x^2 + 2

State the range of y = x^2 + 2

Domain is R and the range is all positive reals greater than or equal to 2.

**In mathematics, you don't understand things. You just get used to them.**

**If it ain't broke, fix it until it is.**

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