Discussion about math, puzzles, games and fun. Useful symbols: ÷ × ½ √ ∞ ≠ ≤ ≥ ≈ ⇒ ± ∈ Δ θ ∴ ∑ ∫ π -¹ ² ³ °

You are not logged in.

- Topics: Active | Unanswered

**Derick Mixon****Member**- Registered: 2013-09-03
- Posts: 65

Can you show me how you would solve this? I have the answers is you want to see them

Offline

**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 81,656

Start by doing the subtraction on the left side.

Now cross multiply.

Factor,

You have x = 0 and x = -2. We reject the 0 solution so x = -2.

**In mathematics, you don't understand things. You just get used to them.I have the result, but I do not yet know how to get it.All physicists, and a good many quite respectable mathematicians are contemptuous about proof.**

Offline

**Derick Mixon****Member**- Registered: 2013-09-03
- Posts: 65

1/2 right?

Offline

**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 81,656

For the first one?

**In mathematics, you don't understand things. You just get used to them.I have the result, but I do not yet know how to get it.All physicists, and a good many quite respectable mathematicians are contemptuous about proof.**

Offline

**Derick Mixon****Member**- Registered: 2013-09-03
- Posts: 65

yes

Offline

**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 81,656

In post #77 I solved it already, the answer is -2.

**In mathematics, you don't understand things. You just get used to them.I have the result, but I do not yet know how to get it.All physicists, and a good many quite respectable mathematicians are contemptuous about proof.**

Offline

**Derick Mixon****Member**- Registered: 2013-09-03
- Posts: 65

ok youre right I see It now what abou the next one

*Last edited by Derick Mixon (2013-09-19 04:04:48)*

Offline

**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 81,656

Give me some time to do the other ones. I will post them right here.

I have the result, but I do not yet know how to get it.

All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

Offline

**Derick Mixon****Member**- Registered: 2013-09-03
- Posts: 65

ok thanks

Offline

**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 81,656

Multiply both sides by 20.

Clean it up.

Add 8 to both sides.

Subtract 5x from both sides.

Divide both sides by 15 and you get x = - ( 17 / 15).

I have the result, but I do not yet know how to get it.

All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

Offline

**Derick Mixon****Member**- Registered: 2013-09-03
- Posts: 65

I have that as well. ok the next question

Offline

**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 81,656

Times both sides by 24.

Add 9 to both sides.

Subtract 8x from both sides.

x = 1

I have the result, but I do not yet know how to get it.

All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

Offline

**Derick Mixon****Member**- Registered: 2013-09-03
- Posts: 65

are you done for the night?

Offline

**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 81,656

Hi;

Yes, I am going to eat.

I have the result, but I do not yet know how to get it.

All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

Offline

**Derick Mixon****Member**- Registered: 2013-09-03
- Posts: 65

Did you do the rest yet?

Offline

**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 81,656

Take 1 / 9 away from both sides.

Flip them both,

x = 3

For the last one:

Times both sides by 15x.

Divide both sides 4.

x = ( 14 / 4 ) = ( 7 / 2 )

I have the result, but I do not yet know how to get it.

All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

Offline

**Derick Mixon****Member**- Registered: 2013-09-03
- Posts: 65

Are you in today?

Offline

**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 81,656

Yes, I am.

I have the result, but I do not yet know how to get it.

All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

Offline

**Derick Mixon****Member**- Registered: 2013-09-03
- Posts: 65

State the domain of y = x2

State the range of y = x2

State the domain of y = x2 + 2

State the range of y = x2 + 2

State the domain of y = 2x2 + 3

State the range of y = 2x2 + 3

State the domain of y = x2 5

State the range of y = x2 - 5

State the domain of y = -x2

State the range of y = x2

Offline

**Derick Mixon****Member**- Registered: 2013-09-03
- Posts: 65

Can you show me how to solve them?

Offline

**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 81,656

What is x2?

I have the result, but I do not yet know how to get it.

All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

Offline

**Derick Mixon****Member**- Registered: 2013-09-03
- Posts: 65

The x value

Offline

**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 81,656

And the 2, is that a power?

I have the result, but I do not yet know how to get it.

All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

Offline

**Derick Mixon****Member**- Registered: 2013-09-03
- Posts: 65

yes

Offline

**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 81,656

State the domain of y = x^2

State the range of y = x^2

I get the domain as R and the range as [0,∞)

State the domain of y = x^2 + 2

State the range of y = x^2 + 2

Domain is R and the range is all positive reals greater than or equal to 2.

I have the result, but I do not yet know how to get it.

All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

Offline