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**Derick Mixon****Member**- Registered: 2013-09-03
- Posts: 65

Can you show me how you would solve this? I have the answers is you want to see them

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 86,491

Start by doing the subtraction on the left side.

Now cross multiply.

Factor,

You have x = 0 and x = -2. We reject the 0 solution so x = -2.

**In mathematics, you don't understand things. You just get used to them.Of course that result can be rigorously obtained, but who cares?Combinatorics is Algebra and Algebra is Combinatorics.**

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**Derick Mixon****Member**- Registered: 2013-09-03
- Posts: 65

1/2 right?

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 86,491

For the first one?

**In mathematics, you don't understand things. You just get used to them.Of course that result can be rigorously obtained, but who cares?Combinatorics is Algebra and Algebra is Combinatorics.**

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**Derick Mixon****Member**- Registered: 2013-09-03
- Posts: 65

yes

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 86,491

In post #77 I solved it already, the answer is -2.

Of course that result can be rigorously obtained, but who cares?

Combinatorics is Algebra and Algebra is Combinatorics.

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**Derick Mixon****Member**- Registered: 2013-09-03
- Posts: 65

ok youre right I see It now what abou the next one

*Last edited by Derick Mixon (2013-09-19 04:04:48)*

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 86,491

Give me some time to do the other ones. I will post them right here.

Of course that result can be rigorously obtained, but who cares?

Combinatorics is Algebra and Algebra is Combinatorics.

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**Derick Mixon****Member**- Registered: 2013-09-03
- Posts: 65

ok thanks

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 86,491

Multiply both sides by 20.

Clean it up.

Add 8 to both sides.

Subtract 5x from both sides.

Divide both sides by 15 and you get x = - ( 17 / 15).

Of course that result can be rigorously obtained, but who cares?

Combinatorics is Algebra and Algebra is Combinatorics.

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**Derick Mixon****Member**- Registered: 2013-09-03
- Posts: 65

I have that as well. ok the next question

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 86,491

Times both sides by 24.

Add 9 to both sides.

Subtract 8x from both sides.

x = 1

Of course that result can be rigorously obtained, but who cares?

Combinatorics is Algebra and Algebra is Combinatorics.

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**Derick Mixon****Member**- Registered: 2013-09-03
- Posts: 65

are you done for the night?

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 86,491

Hi;

Yes, I am going to eat.

Of course that result can be rigorously obtained, but who cares?

Combinatorics is Algebra and Algebra is Combinatorics.

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**Derick Mixon****Member**- Registered: 2013-09-03
- Posts: 65

Did you do the rest yet?

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 86,491

Take 1 / 9 away from both sides.

Flip them both,

x = 3

For the last one:

Times both sides by 15x.

Divide both sides 4.

x = ( 14 / 4 ) = ( 7 / 2 )

Of course that result can be rigorously obtained, but who cares?

Combinatorics is Algebra and Algebra is Combinatorics.

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**Derick Mixon****Member**- Registered: 2013-09-03
- Posts: 65

Are you in today?

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 86,491

Yes, I am.

Of course that result can be rigorously obtained, but who cares?

Combinatorics is Algebra and Algebra is Combinatorics.

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**Derick Mixon****Member**- Registered: 2013-09-03
- Posts: 65

State the domain of y = x2

State the range of y = x2

State the domain of y = x2 + 2

State the range of y = x2 + 2

State the domain of y = 2x2 + 3

State the range of y = 2x2 + 3

State the domain of y = x2 5

State the range of y = x2 - 5

State the domain of y = -x2

State the range of y = x2

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**Derick Mixon****Member**- Registered: 2013-09-03
- Posts: 65

Can you show me how to solve them?

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 86,491

What is x2?

Of course that result can be rigorously obtained, but who cares?

Combinatorics is Algebra and Algebra is Combinatorics.

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**Derick Mixon****Member**- Registered: 2013-09-03
- Posts: 65

The x value

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 86,491

And the 2, is that a power?

Of course that result can be rigorously obtained, but who cares?

Combinatorics is Algebra and Algebra is Combinatorics.

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**Derick Mixon****Member**- Registered: 2013-09-03
- Posts: 65

yes

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 86,491

State the domain of y = x^2

State the range of y = x^2

I get the domain as R and the range as [0,∞)

State the domain of y = x^2 + 2

State the range of y = x^2 + 2

Domain is R and the range is all positive reals greater than or equal to 2.

Of course that result can be rigorously obtained, but who cares?

Combinatorics is Algebra and Algebra is Combinatorics.

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