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**ganesh****Administrator**- Registered: 2005-06-28
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CG # 1

Find the area of the triangle whose vertices are

(2, -3), (-1, 3) and (4, 7).

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**krassi_holmz****Real Member**- Registered: 2005-12-02
- Posts: 1,905

21

IPBLE: Increasing Performance By Lowering Expectations.

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**ganesh****Administrator**- Registered: 2005-06-28
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It is no good to try to stop knowledge from going forward. Ignorance is never better than knowledge - Enrico Fermi.

Nothing is better than reading and gaining more and more knowledge - Stephen William Hawking.

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**krassi_holmz****Real Member**- Registered: 2005-12-02
- Posts: 1,905

That was easy. I solved it in Paint for~1min

IPBLE: Increasing Performance By Lowering Expectations.

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**ganesh****Administrator**- Registered: 2005-06-28
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CG # 2

Find (x,y) if (3,2), (6,3), (x,y) and (6,5) are the vertices of a parellologram taken in order.

It is no good to try to stop knowledge from going forward. Ignorance is never better than knowledge - Enrico Fermi.

Nothing is better than reading and gaining more and more knowledge - Stephen William Hawking.

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**krassi_holmz****Real Member**- Registered: 2005-12-02
- Posts: 1,905

{3,4}?

IPBLE: Increasing Performance By Lowering Expectations.

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**ganesh****Administrator**- Registered: 2005-06-28
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Nothing is better than reading and gaining more and more knowledge - Stephen William Hawking.

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**mathsyperson****Moderator**- Registered: 2005-06-22
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(9,6)?

Why did the vector cross the road?

It wanted to be normal.

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**ganesh****Administrator**- Registered: 2005-06-28
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Correct, mathsyperson!

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**ganesh****Administrator**- Registered: 2005-06-28
- Posts: 25,334

CG # 3

If 3x-2y+4=0 and ax+4y+3=0 are parallel lines, find the value of a.

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**Patrick****Real Member**- Registered: 2006-02-24
- Posts: 1,005

CG# 3

a = -6?

*Last edited by Patrick (2006-03-01 06:17:20)*

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**ganesh****Administrator**- Registered: 2005-06-28
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You're correct, Patrick! Well done!

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**ganesh****Administrator**- Registered: 2005-06-28
- Posts: 25,334

CG # 4

Find the equations of the lines which pass through the point (3,4) and make intercepts on the axes such that their sum is 14.

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**ryos****Member**- Registered: 2005-08-04
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El que pega primero pega dos veces.

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**ganesh****Administrator**- Registered: 2005-06-28
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They are the only equations for which the conditions work

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**ganesh****Administrator**- Registered: 2005-06-28
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CG # 5

Find the equation of the perpendicular bisector of the line joining the points A(-1,2) and B(3,-4).

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**Dionysus****Member**- Registered: 2006-03-06
- Posts: 9

*Last edited by Dionysus (2006-03-06 16:22:49)*

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**ganesh****Administrator**- Registered: 2005-06-28
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*Excellent, Dionysus! *

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**ganesh****Administrator**- Registered: 2005-06-28
- Posts: 25,334

CG # 6

Prove that the lines 3x-4y+5=0, 7x-8y+5=0 and 4x+5y=45 are concurrent.

Nothing is better than reading and gaining more and more knowledge - Stephen William Hawking.

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**ganesh****Administrator**- Registered: 2005-06-28
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CG # 7

Show that the points (4, -4), (-4, 4), and (4√3, 4√3) are the vertices of an equilateral triangle.

Nothing is better than reading and gaining more and more knowledge - Stephen William Hawking.

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**Dionysus****Member**- Registered: 2006-03-06
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**ganesh****Administrator**- Registered: 2005-06-28
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Nothing is better than reading and gaining more and more knowledge - Stephen William Hawking.

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**ganesh****Administrator**- Registered: 2005-06-28
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CG # 8

Find the equation of the straight line making an angle 135° with the positive direction of x-axis and cutting an intercept 5 on the y-axis.

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**mathsyperson****Moderator**- Registered: 2005-06-22
- Posts: 4,900

tan 135° = -1, so that is the gradient of the line. We are told that the y-intercept is 5, so the equation is y = 5-x.

Why did the vector cross the road?

It wanted to be normal.

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**ganesh****Administrator**- Registered: 2005-06-28
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**Very good, mathsyperson!**

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