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#1 2006-02-27 16:44:14

ganesh
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Registered: 2005-06-28
Posts: 13,276

Coordinate Geometry

CG # 1

Find the area of the triangle whose vertices are
(2, -3), (-1, 3) and (4, 7).


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#2 2006-02-27 18:32:13

krassi_holmz
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Registered: 2005-12-02
Posts: 1,908

Re: Coordinate Geometry

21


IPBLE:  Increasing Performance By Lowering Expectations.

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#3 2006-02-27 19:45:29

ganesh
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Re: Coordinate Geometry

kk-neatwork.gif


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#4 2006-02-27 20:17:05

krassi_holmz
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Registered: 2005-12-02
Posts: 1,908

Re: Coordinate Geometry

That was easy. I solved it in Paint for~1min


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#5 2006-02-28 16:17:19

ganesh
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Registered: 2005-06-28
Posts: 13,276

Re: Coordinate Geometry

CG # 2

Find (x,y) if (3,2), (6,3), (x,y) and (6,5) are the vertices of a parellologram taken in order.


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#6 2006-02-28 17:59:51

krassi_holmz
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Re: Coordinate Geometry

{3,4}?


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#7 2006-02-28 19:41:06

ganesh
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Re: Coordinate Geometry

try.jpg


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#8 2006-03-01 03:37:59

mathsyperson
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Registered: 2005-06-22
Posts: 4,900

Re: Coordinate Geometry

(9,6)?


Why did the vector cross the road?
It wanted to be normal.

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#9 2006-03-01 03:46:38

ganesh
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Re: Coordinate Geometry

Correct, mathsyperson! smile smile smile


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#10 2006-03-01 04:00:29

ganesh
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Registered: 2005-06-28
Posts: 13,276

Re: Coordinate Geometry

CG # 3

If 3x-2y+4=0 and ax+4y+3=0 are parallel lines, find the value of a.


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#11 2006-03-01 06:17:02

Patrick
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Registered: 2006-02-24
Posts: 1,005

Re: Coordinate Geometry

CG# 3
a = -6?

Last edited by Patrick (2006-03-01 06:17:20)


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#12 2006-03-01 15:59:53

ganesh
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Re: Coordinate Geometry

You're correct, Patrick! Well done! up


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#13 2006-03-01 16:13:04

ganesh
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Registered: 2005-06-28
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Re: Coordinate Geometry

CG # 4

Find the equations of the lines which pass through the point (3,4) and make intercepts on the axes such that their sum is 14.


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#14 2006-03-01 18:08:18

ryos
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Registered: 2005-08-04
Posts: 394

Re: Coordinate Geometry


El que pega primero pega dos veces.

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#15 2006-03-01 18:25:24

ganesh
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Registered: 2005-06-28
Posts: 13,276

Re: Coordinate Geometry

f40w_well_done.jpg

They are the only equations for which the conditions work


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#16 2006-03-02 17:39:04

ganesh
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Registered: 2005-06-28
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Re: Coordinate Geometry

CG # 5

Find the equation of the perpendicular bisector of the line joining the points A(-1,2) and B(3,-4).


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#17 2006-03-06 16:22:15

Dionysus
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Registered: 2006-03-06
Posts: 9

Re: Coordinate Geometry

Last edited by Dionysus (2006-03-06 16:22:49)

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#18 2006-03-06 16:50:37

ganesh
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Registered: 2005-06-28
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Re: Coordinate Geometry

Excellent, Dionysus! up cool roflol


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#19 2006-03-06 18:31:40

ganesh
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Registered: 2005-06-28
Posts: 13,276

Re: Coordinate Geometry

CG # 6

Prove that the lines 3x-4y+5=0, 7x-8y+5=0 and 4x+5y=45 are concurrent.


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#20 2006-03-08 20:02:03

ganesh
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Re: Coordinate Geometry

CG # 7

Show that the points (4, -4), (-4, 4), and (4√3, 4√3) are the vertices of an equilateral triangle.


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#21 2006-03-09 16:50:39

Dionysus
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Registered: 2006-03-06
Posts: 9

Re: Coordinate Geometry

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#22 2006-03-10 03:00:46

ganesh
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Registered: 2005-06-28
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Re: Coordinate Geometry

kk-neatwork.gif


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#23 2006-03-10 04:27:36

ganesh
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Registered: 2005-06-28
Posts: 13,276

Re: Coordinate Geometry

CG # 8

Find the equation of the straight line making an angle 135° with the positive direction of x-axis and cutting an intercept 5 on the y-axis.


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#24 2006-03-10 04:31:37

mathsyperson
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Registered: 2005-06-22
Posts: 4,900

Re: Coordinate Geometry

tan 135° = -1, so that is the gradient of the line. We are told that the y-intercept is 5, so the equation is y = 5-x.


Why did the vector cross the road?
It wanted to be normal.

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#25 2006-03-10 15:50:29

ganesh
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Registered: 2005-06-28
Posts: 13,276

Re: Coordinate Geometry

Very good, mathsyperson!


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