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#1 2006-02-28 15:44:14

ganesh
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Coordinate Geometry

CG # 1

Find the area of the triangle whose vertices are
(2, -3), (-1, 3) and (4, 7).


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#2 2006-02-28 17:32:13

krassi_holmz
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Re: Coordinate Geometry

21


IPBLE:  Increasing Performance By Lowering Expectations.
 

#3 2006-02-28 18:45:29

ganesh
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Re: Coordinate Geometry

http://www.ourhutch.com/kidkrossing/kk-neatwork.gif


Character is who you are when no one is looking.
 

#4 2006-02-28 19:17:05

krassi_holmz
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Re: Coordinate Geometry

That was easy. I solved it in Paint for~1min


IPBLE:  Increasing Performance By Lowering Expectations.
 

#5 2006-03-01 15:17:19

ganesh
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Re: Coordinate Geometry

CG # 2

Find (x,y) if (3,2), (6,3), (x,y) and (6,5) are the vertices of a parellologram taken in order.


Character is who you are when no one is looking.
 

#6 2006-03-01 16:59:51

krassi_holmz
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Re: Coordinate Geometry

{3,4}?


IPBLE:  Increasing Performance By Lowering Expectations.
 

#7 2006-03-01 18:41:06

ganesh
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Re: Coordinate Geometry

http://www.people.ku.edu/~ctung/try.jpg


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#8 2006-03-02 02:37:59

mathsyperson
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Re: Coordinate Geometry

(9,6)?


Why did the vector cross the road?
It wanted to be normal.
 

#9 2006-03-02 02:46:38

ganesh
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Re: Coordinate Geometry

Correct, mathsyperson! smile smile smile


Character is who you are when no one is looking.
 

#10 2006-03-02 03:00:29

ganesh
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Re: Coordinate Geometry

CG # 3

If 3x-2y+4=0 and ax+4y+3=0 are parallel lines, find the value of a.


Character is who you are when no one is looking.
 

#11 2006-03-02 05:17:02

Patrick
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Re: Coordinate Geometry

CG# 3
a = -6?

Last edited by Patrick (2006-03-02 05:17:20)


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#12 2006-03-02 14:59:53

ganesh
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Re: Coordinate Geometry

You're correct, Patrick! Well done! up


Character is who you are when no one is looking.
 

#13 2006-03-02 15:13:04

ganesh
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Re: Coordinate Geometry

CG # 4

Find the equations of the lines which pass through the point (3,4) and make intercepts on the axes such that their sum is 14.


Character is who you are when no one is looking.
 

#14 2006-03-02 17:08:18

ryos
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Re: Coordinate Geometry


El que pega primero pega dos veces.
 

#15 2006-03-02 17:25:24

ganesh
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Re: Coordinate Geometry

http://www.stampingmad.co.uk/acatalog/f40w_well_done.jpg

They are the only equations for which the conditions work


Character is who you are when no one is looking.
 

#16 2006-03-03 16:39:04

ganesh
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Re: Coordinate Geometry

CG # 5

Find the equation of the perpendicular bisector of the line joining the points A(-1,2) and B(3,-4).


Character is who you are when no one is looking.
 

#17 2006-03-07 15:22:15

Dionysus
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Re: Coordinate Geometry

Last edited by Dionysus (2006-03-07 15:22:49)

 

#18 2006-03-07 15:50:37

ganesh
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Re: Coordinate Geometry

Excellent, Dionysus! up cool roflol


Character is who you are when no one is looking.
 

#19 2006-03-07 17:31:40

ganesh
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Re: Coordinate Geometry

CG # 6

Prove that the lines 3x-4y+5=0, 7x-8y+5=0 and 4x+5y=45 are concurrent.


Character is who you are when no one is looking.
 

#20 2006-03-09 19:02:03

ganesh
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Re: Coordinate Geometry

CG # 7

Show that the points (4, -4), (-4, 4), and (4√3, 4√3) are the vertices of an equilateral triangle.


Character is who you are when no one is looking.
 

#21 2006-03-10 15:50:39

Dionysus
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Re: Coordinate Geometry

 

#22 2006-03-11 02:00:46

ganesh
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Re: Coordinate Geometry

http://www.ourhutch.com/kidkrossing/kk-neatwork.gif


Character is who you are when no one is looking.
 

#23 2006-03-11 03:27:36

ganesh
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Re: Coordinate Geometry

CG # 8

Find the equation of the straight line making an angle 135 with the positive direction of x-axis and cutting an intercept 5 on the y-axis.


Character is who you are when no one is looking.
 

#24 2006-03-11 03:31:37

mathsyperson
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Re: Coordinate Geometry

tan 135 = -1, so that is the gradient of the line. We are told that the y-intercept is 5, so the equation is y = 5-x.


Why did the vector cross the road?
It wanted to be normal.
 

#25 2006-03-11 14:50:29

ganesh
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Re: Coordinate Geometry

Very good, mathsyperson!


Character is who you are when no one is looking.
 

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