Discussion about math, puzzles, games and fun. Useful symbols: ÷ × ½ √ ∞ ≠ ≤ ≥ ≈ ⇒ ± ∈ Δ θ ∴ ∑ ∫ π -¹ ² ³ °

You are not logged in.

- Topics: Active | Unanswered

- Index
- » Help Me !
- »
**Weird Area**

Pages: **1**

**Maburo****Member**- From: Alberta, Canada
- Registered: 2013-01-08
- Posts: 287

This is just a question I thought up, but couldn't figure out how to answer:

A parabola whose vertex lies along the the graph of

What value of c will maximize the area between f(x) and g(x), where f(x)>g(x)? In other words, the area enclosed beneath f(x) and above g(x).

"Pure mathematics is, in its way, the poetry of logical ideas."

-Albert Einstein

Offline

**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 106,366

Hi Maburo;

**In mathematics, you don't understand things. You just get used to them.****If it ain't broke, fix it until it is.****No great discovery was ever made without a bold guess. **

**Online**

**Maburo****Member**- From: Alberta, Canada
- Registered: 2013-01-08
- Posts: 287

That is where I was having troubles with it.

Is there a way to approximate it without computer software?

"Pure mathematics is, in its way, the poetry of logical ideas."

-Albert Einstein

Offline

**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 106,366

An approximate solution is synonymous with computer. Geogebra can answer the question quick and easy. You have 2 non linear equations they are not usually solvable in analytical form.

**In mathematics, you don't understand things. You just get used to them.****If it ain't broke, fix it until it is.****No great discovery was ever made without a bold guess. **

**Online**

Pages: **1**

- Index
- » Help Me !
- »
**Weird Area**