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#1 2014-07-07 03:06:26

Maburo
Member
From: Alberta, Canada
Registered: 2013-01-08
Posts: 286

Weird Area

This is just a question I thought up, but couldn't figure out how to answer:

A parabola whose vertex lies along the the graph of

What value of c will maximize the area between f(x) and g(x), where f(x)>g(x)? In other words, the area enclosed beneath f(x) and above g(x).


"Pure mathematics is, in its way, the poetry of logical ideas."
-Albert Einstein

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#2 2014-07-07 22:34:08

bobbym
Administrator
From: Bumpkinland
Registered: 2009-04-12
Posts: 87,248

Re: Weird Area

Hi Maburo;


In mathematics, you don't understand things. You just get used to them.
Of course that result can be rigorously obtained, but who cares?
Combinatorics is Algebra and Algebra is Combinatorics.

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#3 2014-07-09 10:40:56

Maburo
Member
From: Alberta, Canada
Registered: 2013-01-08
Posts: 286

Re: Weird Area

That is where I was having troubles with it.

Is there a way to approximate it without computer software?


"Pure mathematics is, in its way, the poetry of logical ideas."
-Albert Einstein

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#4 2014-07-09 18:47:01

bobbym
Administrator
From: Bumpkinland
Registered: 2009-04-12
Posts: 87,248

Re: Weird Area

An approximate solution is synonymous with computer. Geogebra can answer the question quick and easy. You have 2 non linear equations they are not usually solvable in analytical form.


In mathematics, you don't understand things. You just get used to them.
Of course that result can be rigorously obtained, but who cares?
Combinatorics is Algebra and Algebra is Combinatorics.

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