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#1 2014-07-07 03:06:26

Maburo
Member
From: Alberta, Canada
Registered: 2013-01-08
Posts: 287

Weird Area

This is just a question I thought up, but couldn't figure out how to answer:

A parabola whose vertex lies along the the graph of

What value of c will maximize the area between f(x) and g(x), where f(x)>g(x)? In other words, the area enclosed beneath f(x) and above g(x).


"Pure mathematics is, in its way, the poetry of logical ideas."
-Albert Einstein

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#2 2014-07-07 22:34:08

bobbym
Administrator
From: Bumpkinland
Registered: 2009-04-12
Posts: 90,562

Re: Weird Area

Hi Maburo;


In mathematics, you don't understand things. You just get used to them.

I agree with you regarding the satisfaction and importance of actually computing some numbers. I can't tell you how often I see time and money wasted because someone didn't bother to run the numbers.

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#3 2014-07-09 10:40:56

Maburo
Member
From: Alberta, Canada
Registered: 2013-01-08
Posts: 287

Re: Weird Area

That is where I was having troubles with it.

Is there a way to approximate it without computer software?


"Pure mathematics is, in its way, the poetry of logical ideas."
-Albert Einstein

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#4 2014-07-09 18:47:01

bobbym
Administrator
From: Bumpkinland
Registered: 2009-04-12
Posts: 90,562

Re: Weird Area

An approximate solution is synonymous with computer. Geogebra can answer the question quick and easy. You have 2 non linear equations they are not usually solvable in analytical form.


In mathematics, you don't understand things. You just get used to them.

I agree with you regarding the satisfaction and importance of actually computing some numbers. I can't tell you how often I see time and money wasted because someone didn't bother to run the numbers.

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