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**EbenezerSon****Member**- Registered: 2013-07-04
- Posts: 456

It seems that brought my mistake!

I know only one thing - that is that I know nothing

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**EbenezerSon****Member**- Registered: 2013-07-04
- Posts: 456

So, by combining them. x^2 - x + x - 1 = x^2-1. is this right Sir?

I know only one thing - that is that I know nothing

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 86,366

The order of operations goes

"Please Excuse My Dear Aunt Sally" or PEMDAS

It says parentheses first then exponentiation so

-x^0 says do the exponentiation ( raising to a power) first and then the minus sign. so it is -1.

**In mathematics, you don't understand things. You just get used to them.Of course that result can be rigorously obtained, but who cares?Combinatorics is Algebra and Algebra is Combinatorics.**

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**EbenezerSon****Member**- Registered: 2013-07-04
- Posts: 456

bobbym wrote:

The order of operations goes

"Please Excuse My Dear Aunt Sally" or PEMDAS

It says parentheses first then exponentiation so

-x^0 says do the exponentiation ( raising to a power) first and then the minus sign. so it is -1.

Please I am not grasping what you mean.

I know only one thing - that is that I know nothing

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 86,366

You raise a number to a power before you do anything other than a parentheses. This is called the order of operations. The ^0 goes first then the - sign.

**In mathematics, you don't understand things. You just get used to them.Of course that result can be rigorously obtained, but who cares?Combinatorics is Algebra and Algebra is Combinatorics.**

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**EbenezerSon****Member**- Registered: 2013-07-04
- Posts: 456

Errr okay. So something like. (x^2 - x + x - x^0)

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 86,366

Yes, that is correct but you simplify it to

x^2 -1

**In mathematics, you don't understand things. You just get used to them.Of course that result can be rigorously obtained, but who cares?Combinatorics is Algebra and Algebra is Combinatorics.**

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**EbenezerSon****Member**- Registered: 2013-07-04
- Posts: 456

So know, please let factorise the denominator.

I know only one thing - that is that I know nothing

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 86,366

Hi;

You do the denominator the same way.

Try using FOIL.

Of course that result can be rigorously obtained, but who cares?

Combinatorics is Algebra and Algebra is Combinatorics.

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**EbenezerSon****Member**- Registered: 2013-07-04
- Posts: 456

With the denominator I had: x^3 - 2x^2 + x.

I know only one thing - that is that I know nothing

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 86,366

That is correct. When you combine the numerator and the denominator you get:

but you are not done because you can simplify further.

Of course that result can be rigorously obtained, but who cares?

Combinatorics is Algebra and Algebra is Combinatorics.

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**EbenezerSon****Member**- Registered: 2013-07-04
- Posts: 456

I must factorise the denominator, and here I go:

x^3 - 2x + x = 0

= x^3 - x^2 - x^2 + x = 0

= x^2(x - 1) - x(x - 1) = 0

Therefore:

(x^2 - x)(x- 1)

Numerator looks like difference of two square. There I go:

(x - 1)(x+ 1)/(x^2 - x)(x- 1) = x + 1/x^2 - x) = x + 1/ x(x - 1) . I hope I am correct.

I know only one thing - that is that I know nothing

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 86,366

That is correct! Very good.

I know they are not stressing anymore but they are wrong. Please bracket it like this:

(x + 1)/ (x(x - 1))

Of course that result can be rigorously obtained, but who cares?

Combinatorics is Algebra and Algebra is Combinatorics.

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**EbenezerSon****Member**- Registered: 2013-07-04
- Posts: 456

Do you mean you can simplify further?.

I know only one thing - that is that I know nothing

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**EbenezerSon****Member**- Registered: 2013-07-04
- Posts: 456

Thank you very much indeed Sir!, in fact you're darling!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

I know only one thing - that is that I know nothing

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 86,366

You are welcome and please call me bobbym. Good night, I need rest.

Of course that result can be rigorously obtained, but who cares?

Combinatorics is Algebra and Algebra is Combinatorics.

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**EbenezerSon****Member**- Registered: 2013-07-04
- Posts: 456

Thanks bobbym, I get you.

I know only one thing - that is that I know nothing

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**EbenezerSon****Member**- Registered: 2013-07-04
- Posts: 456

Please help me solve the following, I can solve, but the 6 has become my headache, I can't figure out how to go about the 6.

.b)

Please, the

has square root on it.Thanks in advance.

Son.

*Last edited by EbenezerSon (2013-07-23 00:45:00)*

I know only one thing - that is that I know nothing

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 86,366

Hi;

Is that what you have?

Of course that result can be rigorously obtained, but who cares?

Combinatorics is Algebra and Algebra is Combinatorics.

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**EbenezerSon****Member**- Registered: 2013-07-04
- Posts: 456

No, the top terms are all on one platform. It was accident that I brought a space between the twenty seven and the rest.

Besides, it is 6.3^3n+3. I missed the sign for negative. I am sorry.

I know only one thing - that is that I know nothing

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 86,366

Is this closer?

Of course that result can be rigorously obtained, but who cares?

Combinatorics is Algebra and Algebra is Combinatorics.

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**EbenezerSon****Member**- Registered: 2013-07-04
- Posts: 456

between the six and the three is multiplication sign. that is only problem.

I know only one thing - that is that I know nothing

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 86,366

So this is the problem:

Of course that result can be rigorously obtained, but who cares?

Combinatorics is Algebra and Algebra is Combinatorics.

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**EbenezerSon****Member**- Registered: 2013-07-04
- Posts: 456

you have taken the negative sign after the six.

I know only one thing - that is that I know nothing

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 86,366

I am not following you. Can you copy the problem as it is written?

Of course that result can be rigorously obtained, but who cares?

Combinatorics is Algebra and Algebra is Combinatorics.

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