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**RauLiTo****Member**- Registered: 2006-01-11
- Posts: 142

hi gus ... how are you ? i wish u r fine

try to get X ?

ImPo$$!BLe = NoTH!nG

Go DowN DeeP iNTo aNyTHinG U WiLL FinD MaTHeMaTiCs ...

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**mathsyperson****Moderator**- Registered: 2005-06-22
- Posts: 4,900

And that's a quartic equation. They can be solved, but the method is very complex. I think I've probably taken the wrong route. That or the quartic can be factorised into something nicer.

Why did the vector cross the road?

It wanted to be normal.

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**irspow****Member**- Registered: 2005-11-24
- Posts: 456

How precise did you wish to be? I tried a couple of different ways and none gave me an exact answer.

Seven iterations of Newton's method, which in this case gave;

(3x^4+4x^3-x^2+3)/(4x^3+6x^2-2x-6) ≈ 1.6180339887499... and -0.6180339887499

using 1 and -1 as starting values of x.

My TI-89 gave (√(5) + 1)/2 and -(√(5) - 1)/2 ( which agrees with above )

Solving your equation for zero gives;

x^4 + 2x^3 - x^2 - 6x - 3 = 0

I don't know the algorithm used by the TI-89 so I had to use Newton's method. I would think that a quartic formula would be more cumbersome than Newton's method, but I am sure that you can find it on the internet easily. In short, I don't see an easy way to solve this.

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**Ricky****Moderator**- Registered: 2005-12-04
- Posts: 3,791

(x²-x-1)(x²+3x+3)

"In the real world, this would be a problem. But in mathematics, we can just define a place where this problem doesn't exist. So we'll go ahead and do that now..."

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**RauLiTo****Member**- Registered: 2006-01-11
- Posts: 142

when i tried to get X that was my answer also ... so i asked you here guys because u may know ... whatever thank you everybody

ImPo$$!BLe = NoTH!nG

Go DowN DeeP iNTo aNyTHinG U WiLL FinD MaTHeMaTiCs ...

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**Tigeree****Member**- Registered: 2005-11-19
- Posts: 13,848

eh, u have a nice signature

People don't notice whether it's winter or summer when they're happy.

~ Anton Chekhov

Cheer up, emo kid.

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