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## #1 2006-01-29 00:11:22

RauLiTo
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### try to get X

hi gus ... how are you ? i wish u r fine

try to get X ?

ImPo\$\$!BLe = NoTH!nG
Go DowN DeeP iNTo aNyTHinG U WiLL FinD MaTHeMaTiCs ...

## #2 2006-01-29 01:05:48

mathsyperson
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### Re: try to get X

And that's a quartic equation. They can be solved, but the method is very complex. I think I've probably taken the wrong route. That or the quartic can be factorised into something nicer.

Why did the vector cross the road?
It wanted to be normal.

## #3 2006-01-29 01:24:01

irspow
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### Re: try to get X

How precise did you wish to be?  I tried a couple of different ways and none gave me an exact answer.

Seven iterations of Newton's method, which in this case gave;

(3x^4+4x^3-x^2+3)/(4x^3+6x^2-2x-6) ≈ 1.6180339887499... and -0.6180339887499

using 1 and -1 as starting values of x.

My TI-89 gave (√(5) + 1)/2 and -(√(5) - 1)/2   ( which agrees with above )

Solving your equation for zero gives;

x^4 + 2x^3 - x^2 - 6x - 3 = 0

I don't know the algorithm used by the TI-89 so I had to use Newton's method.  I would think that a quartic formula would be more cumbersome than Newton's method, but I am sure that you can find it on the internet easily.  In short, I don't see an easy way to solve this.

## #4 2006-01-29 03:09:35

Ricky
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### Re: try to get X

(x²-x-1)(x²+3x+3)

"In the real world, this would be a problem.  But in mathematics, we can just define a place where this problem doesn't exist.  So we'll go ahead and do that now..."

## #5 2006-01-30 19:38:49

RauLiTo
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### Re: try to get X

when i tried to get X that was my answer also ... so i asked you here guys because u may know ... whatever thank you everybody

ImPo\$\$!BLe = NoTH!nG
Go DowN DeeP iNTo aNyTHinG U WiLL FinD MaTHeMaTiCs ...

## #6 2006-01-31 18:19:22

Tigeree
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### Re: try to get X

eh, u have a nice signature

People don't notice whether it's winter or summer when they're happy.
~ Anton Chekhov
Cheer up, emo kid.