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**bobbym****bumpkin**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 109,606

Yes for 7, that is what I did.

I am not following 8, where did you put C?

**In mathematics, you don't understand things. You just get used to them.****If it ain't broke, fix it until it is.**** Always satisfy the Prime Directive of getting the right answer above all else.**

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**bob bundy****Moderator**- Registered: 2010-06-20
- Posts: 8,006

AMC = 90

Bob

Children are not defined by school ...........The Fonz

You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei

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**zee-f****Member**- Registered: 2011-05-12
- Posts: 1,220

I put C on the circle so from m to b that is 1

One, who adopts patience, will never be deprived of success though it may take a long time to reach him. Imam ali (as)<3

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**zee-f****Member**- Registered: 2011-05-12
- Posts: 1,220

ooooh but the radius of the circle is half the diameter So from M to c that is 2

One, who adopts patience, will never be deprived of success though it may take a long time to reach him. Imam ali (as)<3

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**bobbym****bumpkin**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 109,606

Okay, I think Bob has something for you.

**In mathematics, you don't understand things. You just get used to them.****If it ain't broke, fix it until it is.**** Always satisfy the Prime Directive of getting the right answer above all else.**

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**bob bundy****Moderator**- Registered: 2010-06-20
- Posts: 8,006

Q8

AMC = 90 You had that in the original diagram.

AM = MC = 1 = radius

So use Pythagoras

Bob

ps. 6F, 7A, 9D all seem to be done and correct.

Children are not defined by school ...........The Fonz

You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei

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**zee-f****Member**- Registered: 2011-05-12
- Posts: 1,220

So that makes it a right triangle So that means I can use the Pythagorean theorum.

1^2 + b^2 = 2^2

1+b^2= 4

b^2= 4-1

b^2=3

b= √3

One, who adopts patience, will never be deprived of success though it may take a long time to reach him. Imam ali (as)<3

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**zee-f****Member**- Registered: 2011-05-12
- Posts: 1,220

lol sorry I posted that before reading post #31 Thank you !

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**bob bundy****Moderator**- Registered: 2010-06-20
- Posts: 8,006

That's OK No apology needed. Great that you spotted this yourself.

But look again at your calculation.

Which side (AM,MC or AC) is the hypotenuse?

Bob

Children are not defined by school ...........The Fonz

You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei

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**zee-f****Member**- Registered: 2011-05-12
- Posts: 1,220

AC is going to be the hypotenuse

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**zee-f****Member**- Registered: 2011-05-12
- Posts: 1,220

So 2^2 +2^2= c^2

4+4= c^2

c^2=8

sqrt 8

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**zee-f****Member**- Registered: 2011-05-12
- Posts: 1,220

#10 I like my answer (D) because I know that 9 is the length of DJ and it is equal to 3√3 *√3

So the other side is 3√3 and the hypotenuse = 3√3 *2 which gives me 6√3 which is 6*sqrt(3)

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**bobbym****bumpkin**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 109,606

Hi;

Isn't 8) 1^2 + 1^2 = c^2?

**In mathematics, you don't understand things. You just get used to them.****If it ain't broke, fix it until it is.**** Always satisfy the Prime Directive of getting the right answer above all else.**

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**zee-f****Member**- Registered: 2011-05-12
- Posts: 1,220

but AM is 2 and Mi is 2 so isn't AI going to be 2^2+2^2

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**bobbym****bumpkin**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 109,606

Hi;

8. If I drew a line segment from A to C, and the radius of circle M was 1, what would line segment AC be?

A sqrt 7

B sqrt 2

C sqrt 8

D sqrt 13

E sqrt 4

F sqrt 3

Aren't they 1 not 2

**In mathematics, you don't understand things. You just get used to them.****If it ain't broke, fix it until it is.**** Always satisfy the Prime Directive of getting the right answer above all else.**

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**zee-f****Member**- Registered: 2011-05-12
- Posts: 1,220

if it 1^2 + 1^2 = c^2 that makes my first answer (b) correct

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**bobbym****bumpkin**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 109,606

From your original drawing AM is 1 and MC is 1 because they are radii. AC is the hypotenuse because it is opposite the right angle. B should be correct. Why did you change?

**In mathematics, you don't understand things. You just get used to them.****If it ain't broke, fix it until it is.**** Always satisfy the Prime Directive of getting the right answer above all else.**

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**zee-f****Member**- Registered: 2011-05-12
- Posts: 1,220

1 is the radius but the diameter is 2

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**bobbym****bumpkin**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 109,606

Hi;

You do not need the diameter.

**In mathematics, you don't understand things. You just get used to them.****If it ain't broke, fix it until it is.**** Always satisfy the Prime Directive of getting the right answer above all else.**

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**zee-f****Member**- Registered: 2011-05-12
- Posts: 1,220

So I add the radius not the diameter to get the hypotenuse ?

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**bob bundy****Moderator**- Registered: 2010-06-20
- Posts: 8,006

hi zee-f

I thought you were still trying to do 8.

I've looked back, and yes you did say (b) hours ago.

Oh dear .... got in a muddle there.

As for 10, that is strange. I cannot find the answer I've got for this.

What's your working?

Bob

You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei

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**bob bundy****Moderator**- Registered: 2010-06-20
- Posts: 8,006

No wait. My mistake

D is good!

Bob

You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei

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**zee-f****Member**- Registered: 2011-05-12
- Posts: 1,220

9 is the length of DJ and it is equal to 3√3 *√3

So the other side is 3√3 and the hypotenuse = 3√3 *2 which gives me 6√3 which is 6*sqrt(3)

I used the Special Right Triangles formula

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**zee-f****Member**- Registered: 2011-05-12
- Posts: 1,220

When I do to much math problems I sometimes get mixed up But thanks for the help guys !

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**zee-f****Member**- Registered: 2011-05-12
- Posts: 1,220

I have 10 more left but I am still working on then lol

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