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#26 2012-10-31 02:44:31
- bobbym
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Re: Circles: Chords, Radii, and Arcs
Yes for 7, that is what I did.
I am not following 8, where did you put C?
In mathematics, you don't understand things. You just get used to them.
Probability is the most important concept in modern science, especially as nobody has the slightest notion what it means.
90% of mathematicians do not understand 90% of currently published mathematics.
#30 2012-10-31 02:52:42
- bobbym
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Re: Circles: Chords, Radii, and Arcs
Okay, I think Bob has something for you.
In mathematics, you don't understand things. You just get used to them.
Probability is the most important concept in modern science, especially as nobody has the slightest notion what it means.
90% of mathematicians do not understand 90% of currently published mathematics.
#31 2012-10-31 02:55:19
- bob bundy
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Re: Circles: Chords, Radii, and Arcs
Q8
AMC = 90 You had that in the original diagram.
AM = MC = 1 = radius
So use Pythagoras
Bob
ps. 6F, 7A, 9D all seem to be done and correct.
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei
#32 2012-10-31 03:01:33
- zee-f
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Re: Circles: Chords, Radii, and Arcs
So that makes it a right triangle So that means I can use the Pythagorean theorum.
1^2 + b^2 = 2^2
1+b^2= 4
b^2= 4-1
b^2=3
b= √3
One, who adopts patience, will never be deprived of success though it may take a long time to reach him. Imam ali (as)<3
#34 2012-10-31 03:07:51
- bob bundy
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Re: Circles: Chords, Radii, and Arcs
That's OK No apology needed. Great that you spotted this yourself.
But look again at your calculation.
Which side (AM,MC or AC) is the hypotenuse?
Bob
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei
#37 2012-10-31 03:34:09
- zee-f
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Re: Circles: Chords, Radii, and Arcs
#10 I like my answer (D) because I know that 9 is the length of DJ and it is equal to 3√3 *√3
So the other side is 3√3 and the hypotenuse = 3√3 *2 which gives me 6√3 which is 6*sqrt(3)
One, who adopts patience, will never be deprived of success though it may take a long time to reach him. Imam ali (as)<3
#38 2012-10-31 03:36:49
- bobbym
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Re: Circles: Chords, Radii, and Arcs
Hi;
Isn't 8) 1^2 + 1^2 = c^2?
In mathematics, you don't understand things. You just get used to them.
Probability is the most important concept in modern science, especially as nobody has the slightest notion what it means.
90% of mathematicians do not understand 90% of currently published mathematics.
#40 2012-10-31 03:51:01
- bobbym
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Re: Circles: Chords, Radii, and Arcs
Hi;
8. If I drew a line segment from A to C, and the radius of circle M was 1, what would line segment AC be?
A sqrt 7
B sqrt 2
C sqrt 8
D sqrt 13
E sqrt 4
F sqrt 3
Aren't they 1 not 2
In mathematics, you don't understand things. You just get used to them.
Probability is the most important concept in modern science, especially as nobody has the slightest notion what it means.
90% of mathematicians do not understand 90% of currently published mathematics.
#42 2012-10-31 03:53:46
- bobbym
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Re: Circles: Chords, Radii, and Arcs
From your original drawing AM is 1 and MC is 1 because they are radii. AC is the hypotenuse because it is opposite the right angle. B should be correct. Why did you change?
In mathematics, you don't understand things. You just get used to them.
Probability is the most important concept in modern science, especially as nobody has the slightest notion what it means.
90% of mathematicians do not understand 90% of currently published mathematics.
#44 2012-10-31 03:58:28
- bobbym
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Re: Circles: Chords, Radii, and Arcs
Hi;
You do not need the diameter.
In mathematics, you don't understand things. You just get used to them.
Probability is the most important concept in modern science, especially as nobody has the slightest notion what it means.
90% of mathematicians do not understand 90% of currently published mathematics.
#46 2012-10-31 04:01:14
- bob bundy
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Re: Circles: Chords, Radii, and Arcs
hi zee-f
I thought you were still trying to do 8.
I've looked back, and yes you did say (b) hours ago.
Oh dear .... got in a muddle there.
As for 10, that is strange. I cannot find the answer I've got for this.
What's your working?
Bob
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei
#48 2012-10-31 04:03:06
- zee-f
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Re: Circles: Chords, Radii, and Arcs
9 is the length of DJ and it is equal to 3√3 *√3
So the other side is 3√3 and the hypotenuse = 3√3 *2 which gives me 6√3 which is 6*sqrt(3)
I used the Special Right Triangles formula
One, who adopts patience, will never be deprived of success though it may take a long time to reach him. Imam ali (as)<3
