
 bobbym
 Administrator
Re: Circles: Chords, Radii, and Arcs
Yes for 7, that is what I did.
I am not following 8, where did you put C?
In mathematics, you don't understand things. You just get used to them. I have the result, but I do not yet know how to get it. All physicists, and a good many quite respectable mathematicians are contemptuous about proof.
 bob bundy
 Moderator
Re: Circles: Chords, Radii, and Arcs
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei
 zeef
 Super Member
Re: Circles: Chords, Radii, and Arcs
I put C on the circle so from m to b that is 1
One, who adopts patience, will never be deprived of success though it may take a long time to reach him. Imam ali (as)<3
 zeef
 Super Member
Re: Circles: Chords, Radii, and Arcs
ooooh but the radius of the circle is half the diameter So from M to c that is 2
One, who adopts patience, will never be deprived of success though it may take a long time to reach him. Imam ali (as)<3
 bobbym
 Administrator
Re: Circles: Chords, Radii, and Arcs
Okay, I think Bob has something for you.
In mathematics, you don't understand things. You just get used to them. I have the result, but I do not yet know how to get it. All physicists, and a good many quite respectable mathematicians are contemptuous about proof.
 bob bundy
 Moderator
Re: Circles: Chords, Radii, and Arcs
Q8
AMC = 90 You had that in the original diagram.
AM = MC = 1 = radius
So use Pythagoras
Bob
ps. 6F, 7A, 9D all seem to be done and correct.
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei
 zeef
 Super Member
Re: Circles: Chords, Radii, and Arcs
So that makes it a right triangle So that means I can use the Pythagorean theorum.
1^2 + b^2 = 2^2 1+b^2= 4
b^2= 41 b^2=3 b= √3
One, who adopts patience, will never be deprived of success though it may take a long time to reach him. Imam ali (as)<3
 zeef
 Super Member
Re: Circles: Chords, Radii, and Arcs
lol sorry I posted that before reading post #31 Thank you !
One, who adopts patience, will never be deprived of success though it may take a long time to reach him. Imam ali (as)<3
 bob bundy
 Moderator
Re: Circles: Chords, Radii, and Arcs
That's OK No apology needed. Great that you spotted this yourself.
But look again at your calculation.
Which side (AM,MC or AC) is the hypotenuse?
Bob
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei
 zeef
 Super Member
Re: Circles: Chords, Radii, and Arcs
AC is going to be the hypotenuse
One, who adopts patience, will never be deprived of success though it may take a long time to reach him. Imam ali (as)<3
 zeef
 Super Member
Re: Circles: Chords, Radii, and Arcs
So 2^2 +2^2= c^2 4+4= c^2 c^2=8 sqrt 8
One, who adopts patience, will never be deprived of success though it may take a long time to reach him. Imam ali (as)<3
 zeef
 Super Member
Re: Circles: Chords, Radii, and Arcs
#10 I like my answer (D) because I know that 9 is the length of DJ and it is equal to 3√3 *√3
So the other side is 3√3 and the hypotenuse = 3√3 *2 which gives me 6√3 which is 6*sqrt(3)
One, who adopts patience, will never be deprived of success though it may take a long time to reach him. Imam ali (as)<3
 bobbym
 Administrator
Re: Circles: Chords, Radii, and Arcs
Hi;
Isn't 8) 1^2 + 1^2 = c^2?
In mathematics, you don't understand things. You just get used to them. I have the result, but I do not yet know how to get it. All physicists, and a good many quite respectable mathematicians are contemptuous about proof.
 zeef
 Super Member
Re: Circles: Chords, Radii, and Arcs
but AM is 2 and Mi is 2 so isn't AI going to be 2^2+2^2
One, who adopts patience, will never be deprived of success though it may take a long time to reach him. Imam ali (as)<3
 bobbym
 Administrator
Re: Circles: Chords, Radii, and Arcs
Hi;
8. If I drew a line segment from A to C, and the radius of circle M was 1, what would line segment AC be? A sqrt 7 B sqrt 2 C sqrt 8 D sqrt 13 E sqrt 4 F sqrt 3
Aren't they 1 not 2
In mathematics, you don't understand things. You just get used to them. I have the result, but I do not yet know how to get it. All physicists, and a good many quite respectable mathematicians are contemptuous about proof.
 zeef
 Super Member
Re: Circles: Chords, Radii, and Arcs
if it 1^2 + 1^2 = c^2 that makes my first answer (b) correct
One, who adopts patience, will never be deprived of success though it may take a long time to reach him. Imam ali (as)<3
 bobbym
 Administrator
Re: Circles: Chords, Radii, and Arcs
From your original drawing AM is 1 and MC is 1 because they are radii. AC is the hypotenuse because it is opposite the right angle. B should be correct. Why did you change?
In mathematics, you don't understand things. You just get used to them. I have the result, but I do not yet know how to get it. All physicists, and a good many quite respectable mathematicians are contemptuous about proof.
 zeef
 Super Member
Re: Circles: Chords, Radii, and Arcs
1 is the radius but the diameter is 2
One, who adopts patience, will never be deprived of success though it may take a long time to reach him. Imam ali (as)<3
 bobbym
 Administrator
Re: Circles: Chords, Radii, and Arcs
Hi;
You do not need the diameter.
In mathematics, you don't understand things. You just get used to them. I have the result, but I do not yet know how to get it. All physicists, and a good many quite respectable mathematicians are contemptuous about proof.
 zeef
 Super Member
Re: Circles: Chords, Radii, and Arcs
So I add the radius not the diameter to get the hypotenuse ?
One, who adopts patience, will never be deprived of success though it may take a long time to reach him. Imam ali (as)<3
 bob bundy
 Moderator
Re: Circles: Chords, Radii, and Arcs
hi zeef
I thought you were still trying to do 8.
I've looked back, and yes you did say (b) hours ago.
Oh dear .... got in a muddle there.
As for 10, that is strange. I cannot find the answer I've got for this.
What's your working?
Bob
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei
 bob bundy
 Moderator
Re: Circles: Chords, Radii, and Arcs
No wait. My mistake
D is good!
Bob
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei
 zeef
 Super Member
Re: Circles: Chords, Radii, and Arcs
9 is the length of DJ and it is equal to 3√3 *√3
So the other side is 3√3 and the hypotenuse = 3√3 *2 which gives me 6√3 which is 6*sqrt(3)
I used the Special Right Triangles formula
One, who adopts patience, will never be deprived of success though it may take a long time to reach him. Imam ali (as)<3
 zeef
 Super Member
Re: Circles: Chords, Radii, and Arcs
When I do to much math problems I sometimes get mixed up But thanks for the help guys !
One, who adopts patience, will never be deprived of success though it may take a long time to reach him. Imam ali (as)<3
 zeef
 Super Member
Re: Circles: Chords, Radii, and Arcs
I have 10 more left but I am still working on then lol
One, who adopts patience, will never be deprived of success though it may take a long time to reach him. Imam ali (as)<3
