Discussion about math, puzzles, games and fun. Useful symbols: ÷ × ½ √ ∞ ≠ ≤ ≥ ≈ ⇒ ± ∈ Δ θ ∴ ∑ ∫ π -¹ ² ³ °

You are not logged in.

- Topics: Active | Unanswered

**szk_kei****Member**- Registered: 2005-11-04
- Posts: 21

>

krassi_holmz wrote:

And we can form something like that for definite integrals:

>

Please visit below

http://www.freewebs.com/keiichi_suzuki/math/sekibun0.html

Offline

**krassi_holmz****Real Member**- Registered: 2005-12-02
- Posts: 1,905

I'll visit this... now

IPBLE: Increasing Performance By Lowering Expectations.

Offline

**krassi_holmz****Real Member**- Registered: 2005-12-02
- Posts: 1,905

Cool. So I was right!

IPBLE: Increasing Performance By Lowering Expectations.

Offline

**szk_kei****Member**- Registered: 2005-11-04
- Posts: 21

This formula is unnatural from a commonsense standpoint, but this is natural if we look at this carefully.

Offline

**krassi_holmz****Real Member**- Registered: 2005-12-02
- Posts: 1,905

Yes, it's just a matter of viewpoint.

IPBLE: Increasing Performance By Lowering Expectations.

Offline

**szk_kei****Member**- Registered: 2005-11-04
- Posts: 21

krassi_holmz wrote:

Yes, it's just a matter of viewpoint.

Thank you

Offline

**szk_kei****Member**- Registered: 2005-11-04
- Posts: 21

Good night

Offline

**szk_kei****Member**- Registered: 2005-11-04
- Posts: 21

The story behind the integral relationship

Please visit below

http://www.freewebs.com/keiichi_suzuki/

Click Bedroom(Profile, etc)

Offline

**szk_kei****Member**- Registered: 2005-11-04
- Posts: 21

Let x=x(t), y=y(t), z=z(t)

then

xyz = ∫xy(dz/dt)dt + ∫yz(dx/dt)dt + ∫zx(dy/dt)dt

= ∫xydz + ∫yzdx + ∫zxdy

xyz means difference of volume of rectangular parallelepipeds.

I do not know what ∫xydz , ∫yzdx and ∫zxdy means.

Offline

**szk_kei****Member**- Registered: 2005-11-04
- Posts: 21

The above expression was posted to a forum of my homepage from some person.

I deleted the message in my error.

Offline

**krassi_holmz****Real Member**- Registered: 2005-12-02
- Posts: 1,905

Good. I guess we can generalize this result for many functions.

Let f_1=f_1(t), f_2=f_2(t), ... ,f_n=f_n(t).

then

*Last edited by krassi_holmz (2006-02-04 19:17:11)*

IPBLE: Increasing Performance By Lowering Expectations.

Offline

**szk_kei****Member**- Registered: 2005-11-04
- Posts: 21

I have removed a message to install a Japanese language pack.

Please visit my site.

http://www.freewebs.com/keiichi_suzuki/

Offline

**MathsIsFun****Administrator**- Registered: 2005-01-21
- Posts: 7,651

Your site is coming along well Keiichi Suzuki. I see you have links to Math Forum and others ... why not a link to this forum?

"The physicists defer only to mathematicians, and the mathematicians defer only to God ..." - Leon M. Lederman

Offline

**szk_kei****Member**- Registered: 2005-11-04
- Posts: 21

I feel so grateful to you for giving me advice.

Now I have put a link to your site from mine.

Offline

**George,Y****Member**- Registered: 2006-03-12
- Posts: 1,306

Cool tool, man.

**X'(y-Xβ)=0**

Offline