Math Is Fun Forum / Permutation Generator

aegiziano1 · 2012-02-08 15:19:32

Hey everyone! I was wondering if someone can help me out. I have a math project and need a little help:
problem:
You are to pick five numbers ranging from 1 to 56 and a magic number ranging from 1 to 52. What you have to do is come up with possible combination that have a sum totaling 147. How many combinations are there? What are the combinations?

I was wondering if can help me start the problem ..... and is there a way to do this on excel or an online program I can use..

gAr · 2012-02-08 18:21:32

Hi aegiziano1,

Are the 5 numbers distinct?

bobbym · 2012-02-08 18:43:31

Hi all;

How many combinations are there?

Generating functions can do this.

What are the combinations?

Unless there are only a few then you will need a computer.

aegiziano1 · 2012-02-09 02:03:32

Hi gAr,

Yes sorry the 5 are distinct. No repeating numbers.

bobbym · 2012-02-09 04:14:01

Hi aegiziano1;

How about the magic number? Is it distinct too?

aegiziano1 · 2012-02-09 14:56:33

Gar,

Yes in the fact that you only pick one magic number but may not be distinct from the other five numbers.......
magic# magic#
random ex: 4 15 25 38 27 4 or 5 9 13 32 45 20

bobbym · 2012-02-09 16:45:08

Hi aegiziano1;

I have everything I need except for one thing. You say combinations, so you mean order does not count, For instance:

1,2,3,4,5,137 is the same as 137,2,3,1,5,4.

aegiziano1 · 2012-02-10 01:27:58

Gar,

Yes order does not matter for the 5 number, but the magic number is at the end ....so technically order matters lol... let me know if this is confusing.......... the problem is like picking numbers for the lottery, for example: Mega Million, and the numbers you pick have to add up to 147

bobbym · 2012-02-10 01:54:48

Hi;

So we have _ _ _ _ _ (magic number)?

Order for the first 5 does not count and magic number on the end. Okay, I think I understand.

aegiziano1 · 2012-02-10 15:13:12

Yes you got it!... Sorry for the confusion ... should have explained it better

bobbym · 2012-02-10 15:43:36

Hi aegiziano1;

I am getting:

aegiziano1 · 2012-02-11 10:36:18

Hi bobym,

Whats your thought process behind the 42113?

bobbym · 2012-02-11 13:36:47

gAr · 2012-02-11 23:57:30

Hi all,

bobbym, 42113 is okay for first five digits and a sum of 147. Aren't we supposed to consider the 6th digit also for totaling?

That way, I get:

bobbym · 2012-02-12 05:28:21

Hi gAr;

Yes, you are right that is a clumsy error on my part.

gAr · 2012-02-12 05:33:02

Hi bobbym,

Okay. It happens to me too.

bobbym · 2012-02-12 05:39:54

Hi;

I do not what the heck I was thinking of. Thanks for spotting that! I guess I got too caught up on trying to find a formula. Of course, I had the wrong GF because I was solving the wrong problem!

Hi aegiziano1;

Use gAr's work in post #14, sorry for the error.

gAr · 2012-02-12 05:45:52

You're welcome!
I'll take a break, see you later.

bobbym · 2012-02-12 05:48:38

See you later,my friend.

aegiziano1 · 2012-02-12 07:47:15

Thanks guys I appreciate it!

bobbym · 2012-02-12 07:50:33

Two of us worked hard on this. One of us solved it and the other one worked like a washing machine...

gAr · 2012-02-12 18:45:13

Enjoyed it.
Hope you wouldn't require the list, which takes about 28 MiB.

Labodmin · 2012-02-14 09:33:02

Dear All
I need help on solving a problem .
I want to arrange numbers
Where there are three names on the vertical side like
W. D. A
1
2
3
I want to perm or combine where there are not more than one digit on the vertical role.

Eg.
W. D. A

1. X
2. X
3. X
Or
W. D. A
1 x
2. X
3. X

Any help please?
Many thanks

bobbym · 2012-02-14 11:50:01

Hi Labodmin;

Welcome to the forum.

I want to arrange numbers

How many numbers are there? Are the numbers different?

If we use the numbers 1,2,3 then we get

I used zeros as space holders so it would line up nice. That is 162 ways.

Labodmin · 2012-02-15 06:26:35

Many thanks
The numbers am looking to perm will be like
W1,w2,w3,1d,2d,3d,1a,2a,3a
The table is like eg
W. D. A
1 X
2. X
3. X

Eg of this second table will be wrong
W D. A
1
2
3. X. X. X

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#1 2012-02-08 15:19:32

Permutation Generator

#2 2012-02-08 18:21:32

Re: Permutation Generator

#3 2012-02-08 18:43:31

Re: Permutation Generator

#4 2012-02-09 02:03:32

Re: Permutation Generator

#5 2012-02-09 04:14:01

Re: Permutation Generator

#6 2012-02-09 14:56:33

Re: Permutation Generator

#7 2012-02-09 16:45:08

Re: Permutation Generator

#8 2012-02-10 01:27:58

Re: Permutation Generator

#9 2012-02-10 01:54:48

Re: Permutation Generator

#10 2012-02-10 15:13:12

Re: Permutation Generator

#11 2012-02-10 15:43:36

Re: Permutation Generator

#12 2012-02-11 10:36:18

Re: Permutation Generator

#13 2012-02-11 13:36:47

Re: Permutation Generator

#14 2012-02-11 23:57:30

Re: Permutation Generator

#15 2012-02-12 05:28:21

Re: Permutation Generator

#16 2012-02-12 05:33:02

Re: Permutation Generator

#17 2012-02-12 05:39:54

Re: Permutation Generator

#18 2012-02-12 05:45:52

Re: Permutation Generator

#19 2012-02-12 05:48:38

Re: Permutation Generator

#20 2012-02-12 07:47:15

Re: Permutation Generator

#21 2012-02-12 07:50:33

Re: Permutation Generator

#22 2012-02-12 18:45:13

Re: Permutation Generator

#23 2012-02-14 09:33:02

Re: Permutation Generator

#24 2012-02-14 11:50:01

Re: Permutation Generator

#25 2012-02-15 06:26:35

Re: Permutation Generator

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