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#2 2005-11-02 15:46:28
- MathsIsFun
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Re: inequality
Code:
[math]1/[a\sqrt{a+b}] + 1/[b\sqrt{b+c}] + 1/[c\sqrt{c+a}] \geq 3/[\sqrt{2abc}][/math]Another tough one from "math" ... where do you get them?
Is the solution possibly geometric?
"The physicists defer only to mathematicians, and the mathematicians defer only to God ..." - Leon M. Lederman