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#1 2005-11-01 16:22:55

math
Member
Registered: 2005-10-17
Posts: 16

inequality

a,b,c>0 . Prove the inequality :
1/[a.\sqrt{a+b}] + 1/[b.\sqrt{b+c}]+1/[c.\sqrt{c+a}]    >=  3/(\sqrt{2abc}

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#2 2005-11-01 16:46:28

MathsIsFun
Administrator
Registered: 2005-01-21
Posts: 7,535

Re: inequality

[math]1/[a\sqrt{a+b}] + 1/[b\sqrt{b+c}] + 1/[c\sqrt{c+a}]  \geq 3/[\sqrt{2abc}][/math]

Another tough one from "math" ... where do you get them?

Is the solution possibly geometric?


"The physicists defer only to mathematicians, and the mathematicians defer only to God ..."  - Leon M. Lederman

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#3 2005-11-01 21:19:52

math
Member
Registered: 2005-10-17
Posts: 16

Re: inequality

the teacher were given me ( can you post the solution )

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