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**inequality**

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**math****Member**- Registered: 2005-10-17
- Posts: 16

a,b,c>0 . Prove the inequality :

1/[a.\sqrt{a+b}] + 1/[b.\sqrt{b+c}]+1/[c.\sqrt{c+a}] >= 3/(\sqrt{2abc}

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**MathsIsFun****Administrator**- Registered: 2005-01-21
- Posts: 7,673

`[math]1/[a\sqrt{a+b}] + 1/[b\sqrt{b+c}] + 1/[c\sqrt{c+a}] \geq 3/[\sqrt{2abc}][/math]`

Another tough one from "math" ... where do you get them?

Is the solution possibly geometric?

"The physicists defer only to mathematicians, and the mathematicians defer only to God ..." - Leon M. Lederman

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**math****Member**- Registered: 2005-10-17
- Posts: 16

the teacher were given me ( can you post the solution )

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