Discussion about math, puzzles, games and fun. Useful symbols: ÷ × ½ √ ∞ ≠ ≤ ≥ ≈ ⇒ ± ∈ Δ θ ∴ ∑ ∫ π -¹ ² ³ °

You are not logged in.

- Topics: Active | Unanswered

Pages: **1**

**Jennifer90****Guest**

Hi,

I need some help on an algebra problem, it's -2/-2^-3 (if that makes any sense). I know that I have to flip it over, but what's confusing me is that the first number is a 2 and I'm not sure how that will affect it. The entire problem is -3^-2-2/-2^-3-2^0, and the book says that the answer is 14 8/9.

Thank you!

-Jen

**John E. Franklin****Member**- Registered: 2005-08-29
- Posts: 3,582

The -2 stays on the top (numerator).

The -2^-3 goes to the top as -2^3.

So now you have -2 times -2^3.

Then -2^3 is -8 because -2 times -2 times -2 is -8.

So that times -2 is 16. So add 16 in the middle term of your

entire problem.

**igloo** **myrtilles** **fourmis**

Offline

**jennifer90****Guest**

thank you!

Pages: **1**