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#1 2005-09-27 04:45:24

Jennifer90
Guest

Help please

Hi,
I need some help on an algebra problem, it's -2/-2^-3 (if that makes any sense).  I know that I have to flip it over, but what's confusing me is that the first number is a 2 and I'm not sure how that will affect it.  The entire problem is -3^-2-2/-2^-3-2^0, and the book says that the answer is 14 8/9.

Thank you!

-Jen

#2 2005-09-27 05:10:46

John E. Franklin
Member
Registered: 2005-08-29
Posts: 3,562

Re: Help please

The -2 stays on the top (numerator).
The -2^-3 goes to the top as -2^3.
So now you have -2 times -2^3.
Then -2^3 is -8 because -2 times -2 times -2 is -8.
So that times -2 is 16.  So add 16 in the middle term of your
entire problem.


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#3 2005-10-02 08:50:31

jennifer90
Guest

Re: Help please

thank you! smile

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