Hi, I need some help on an algebra problem, it's -2/-2^-3 (if that makes any sense). I know that I have to flip it over, but what's confusing me is that the first number is a 2 and I'm not sure how that will affect it. The entire problem is -3^-2-2/-2^-3-2^0, and the book says that the answer is 14 8/9.
The -2 stays on the top (numerator). The -2^-3 goes to the top as -2^3. So now you have -2 times -2^3. Then -2^3 is -8 because -2 times -2 times -2 is -8. So that times -2 is 16. So add 16 in the middle term of your entire problem.