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Thanks a lot for the tips, they sure did help!
and thanks for the exercises Identity
just a fast question, in ex. 4 i can only find the factor x-3, is that the only one?
When you want to factor a polynom, are there any rules of how to progress? I know the common ones (like a^2+2ab+b^2=(a+b)^2), but i have problems with a bit advanced ones.
for example m^4 - 2m^3 - m^2 + 2m + 1 = 0
can be factored as follows:
(m^2 - m - 1)^2 = 0
It is easy to check that this example is correct, but how do you progress to find the answer? Are there any rules, or do I just need to practice to be able to see the factorization automatically??
really need to get better at this for a math competion next week...
and if you could make a few exercises it would be great
thanks
4. induction base for 1: n(4*n²-1)/3=1(4*1-1)/3=1
now if we increase n with 1, the sum should increase with (2(n+1)-1)²=(2n+1)²
we replace n in n(4*n²-1)/3 with n+1:
(n+1)(4(n+1)²-1)/3= (n+1)(4n²+8n+4-1)/3=
( n(4n-1) + 8n²+4n+4n²+8n+4-1 )/3=
( n(4n-1) + 12n²+12n+3 )/3=
n(4n-1)/3 + 4n²+4n+1=
n(4n-1)/3 + (2n+1)²
keep posting these ganesh!
2. if n=1 then n(n^2-1)=0 which is divisible by 24.
we also know that n(n^2-1)=n(n-1)(n+1)
Now we need to show that it is divisible with 24 for the next odd number, so we insert n+2 instead of n, which results in:
(n+2)(n+1)(n+3)
we now have two consecutive even numbers, which means that one of them is divisible with 2, and one with 4. These three numbers are also three consecutive numbers, which means that one of them is divisible with 3. 2*4*3=24
i thought about that one too ma+th but i think it wouldnt work since it is two boxes. You cant really take two boxes and put them through eachother
okey i looked at the version at this website, and it actually has one more clue than the one at noggintwisters. I tested it and solved it on ~10 minutes. annoying
im sorry to bring up an old topic, but i get a lot of different solutions. The problem was on noggintwister and i can make different combinations that all follow the "rules" and all gives different answers....have i missed something, or are the clues wrong? and is that alergic thing, is that some kind of clue?
When I am programming my computer cant handle big numbers. If i do an operation where the result exceeds maybe ~10 digits, i get a negative value or just a wrong value. Why cant the computer handle greater numbers? How can i make them do that? I am using Delphi 7. Any help would be appreciated!
well actually its true that E=F since in both cases the "values" are the same but E is filled with air, and F is filled with a liquid
they never came, they have always existed. We only found them...
an easy and fast approximation of pi that i use is 3+1/7
not that accurate but usually accurate enough
I prefer pi.
thats interesting. Since pi has an infinite number of decimals, wouldnt it exist a place (or an infinte number of places) after a number of decimals where pi (or any irrational number) is a palindrome?
and on topic:
what if the time has existed forever? (and with forever i dont mean since the
time started, i mean that the time never started since it has always existed )
i dont think there need to be any other lifeforms in the universe (it can be so, and i want it, but it doesnt NEED to be like that as some people may think).
lets say there are many, up to billions, paralell universes (or why not an infinite amount of universes?). then lets say that life occurs in one out of 1000000 of these universes, then the chance that there might be life on another place in our universe isnt that big...
Or lets say that this universe will close after a while, since it's now expanding it will implode and when it has shrinked to a dot another big bang occurs and a new universe is created and so it continues. Which means that there have been alot of other universes before this one. Then maybe only 1 out of 1000000 of these universes will have a planet that supports life and then the chance that there may be life on two places in this universe is really low again .
But if this universe is the only one that exists i beleive that there may have been life on other places but if i remember correctly earth existed for a long time before life started to exist and lets say that life will be over on earth in maybe 1000-10000 years, then the period that life exists is very short and the chances they will exist at the same time as us isnt that big (ofcourse life on earth may stay here forever, but at least the chances that there will exist two civilizations at the same time in a universe is imo minimal. but not to forget, the distances in our universe are really huge and then you cant really define what exists at the same time since time is relative, right? )
Ofcourse the chances that a universe will support life may not be that minimal as i assumed, but the point is that we have really no idea how life really comes up, we really dont know the deepest secrets of life so we can only roughly calculate that chances that a star sould hold a habitable planet, but there may be loads of more conditions that is needed for life that we dont know yet. i only want to prove for all people that are deadly sure we are not alone that this might not be the case.
and as JaneFairfax said, what is life? how do we really define life? is it something that moves, eats, that has a metabolism. The storm systems on jupiter and neptune, that have big storms that appear and disappear, is that life? All life on earth are anyway made by atoms and molecules so you could say that life on earth and the whole evolution may just be a huge mega-advanced chemical reaction.
the answer to that is simple:
42
(ok, old, i know, but still funny! )
Thanks for the tip Jane.
I really liked exercise 2 and 3, i really need to practise proving these types of problems. i would really appreciate if you could create more exercises like them
Youre more or less on the correct line of thought. However the problem is to show that c is divisible by ab. Its true that ab is less than or equal to c, but this doesnt show that c is divisible by ab.
Ive already given a short solution using Bézouts identity.
well since ab is created by the prime factors in c, c must be divisible by ab?
1. every number that isnt a prime can be factorized in its prime factors, for example 36 can be factorized in 2*2*3*3.
so the number c can be factorized in the prime factors P1*P2*P3.....Pn
a and b are relatively prime so they cant have one same prime factor, but since c is divisible by both a and b, they must be created by one or some of the prime factors in c. therefor a*b can never be more than c.
for example a can be P1*P2 and b can be P3*P4. if we divide c with a and b there will still be P5*P6*....*Pn left.
but if a is P1*P2, b cant be for example P2*P3 since then both will have P2 as a prime factor.
would this be a correct proof?? still practising
try the same problem but instead of the perimeter, the diagonal is the same on the square and the rectangle!
(this was the problem i first solved since i thought perimeter meant diagonal )
I have heard there are some very old theorems that have not been proven and that there is a prize if you prove one. Im just curoius on what kind of problems they are. Can anyone give me a link to them with a good description??
i guessed on:
Here is my solution:
the derivative of the function will be the same as -tan for the corner in the tangent, since
B=angle of refraction
i dont get it
nicely done, and cool "animation"
i think I got the same graph as you, altough my function is way different from your..interesting
here is a math/physics problem or exercise that i made:p
You have a disc made of glass formed as shown in the picture. The edge of the disc is described by the function 4 - x².
a light beam is launched straight down at the point (x,f(x)) where it is refracted and hits the X-axle.
Your task is to describe how the distance a depends on the distance x, in other words the function a(x)
the law of refraction is:
i will post my solution later