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You are not logged in. #1 20071012 03:26:56
Mathematical Induction Vol.I1. For any natural number n, prove that Character is who you are when no one is looking. #2 20071012 03:46:36
Re: Mathematical Induction Vol.I1. proof 5^(2n)6n+8 is divisible by 9. Last edited by mikau (20071012 03:49:45) A logarithm is just a misspelled algorithm. #3 20071012 04:28:41
Re: Mathematical Induction Vol.ISo if n is a volume Mathematical Induction, is n+1? "In the real world, this would be a problem. But in mathematics, we can just define a place where this problem doesn't exist. So we'll go ahead and do that now..." #4 20071012 13:21:47
Re: Mathematical Induction Vol.I2. proof n(n²1) is divisible by 24 for any odd integer n Last edited by mikau (20071012 13:23:56) A logarithm is just a misspelled algorithm. #5 20071013 01:05:21
Re: Mathematical Induction Vol.Iproof 1²+2²+3²+4²+5²+.....n²=[n(n+1)(2n+1)]/6. Last edited by mikau (20071013 01:05:41) A logarithm is just a misspelled algorithm. #6 20071013 03:19:16
Re: Mathematical Induction Vol.Ihehe, how many more do i need to get a Ganesh award? A logarithm is just a misspelled algorithm. #7 20071016 04:59:14
Re: Mathematical Induction Vol.II'll skip 4 for now because its boring and laborious. Last edited by mikau (20071016 05:01:41) A logarithm is just a misspelled algorithm. #8 20071027 08:49:11
Re: Mathematical Induction Vol.I2. if n=1 then n(n^21)=0 which is divisible by 24. Last edited by Kurre (20071027 18:45:21) #9 20071027 19:41:00
Re: Mathematical Induction Vol.I4. induction base for 1: n(4*n²1)/3=1(4*11)/3=1 Last edited by Kurre (20071027 19:41:28) 