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#176 Re: Help Me ! » QUESTION to think about » 2006-10-13 03:26:55

thanks smile i guess i was using the very very long way

#177 Help Me ! » QUESTION to think about » 2006-10-13 03:12:35

unique
Replies: 6

how many different ways can the numbers 1,2,3,4 be arranged if you use each number only once?

i got
1,2,3,4
4,1,2,3
3,4,1,2
2,3,4,1
2,1,4,3
1,4,2,3
3,1,4,2
4,3,2,1

any other ways?
and how many can there be....if we just guessed?

#178 Re: Help Me ! » system of equations » 2006-10-13 02:38:30

a = 3
so put in the value in the equation:
3a - 4c = 7
3(3) - 4c = 7
9 - 4c = 7
subtract 9 both sides
-4c = -2
divide
c = 0.5 or 1/2 right

then c = 0.5
put in value

b - 2c = 1
b - 2(0.5) = 1
b - 1 = 1
add 1 both sides
b = 2 correct

THANKS smile

#179 Re: Help Me ! » system of equations » 2006-10-13 02:09:38

it cant be this way right?

  a - b = 1
-      b - 2c = 1   cross out the b's
------------------
a - 2c = 0 ????

#180 Help Me ! » system of equations » 2006-10-13 02:06:51

unique
Replies: 3

ok i know how to solve system of equations but with this one i am having problems !

1) a - b = 1
2) b - 2c = 1
3) 3a - 4c = 7

ok i know that
you have to first
1equation subtract 2equation
and then
2equation plus 3equation
i know that
but you see that in each equation one letter is missing
so how can we
subtract a-b=1 from b-2c=1
is we dont have a or c????

and same goes for the second part

help:/dunno

#181 Re: Help Me ! » simplify......am i right? » 2006-10-13 01:15:21

ok i understand now smile thanks you guys

#184 Re: Help Me ! » right? » 2006-10-12 05:42:59

ok so the inverse is?
if
2/2 = 1

so
x = y - 1
then
y = x - 1 as inverse ??

#186 Help Me ! » right? » 2006-10-12 05:14:42

unique
Replies: 3

find the inverse function of
y =  2x + 2

original function
y = 2x + 2

rearranged
2x = y - 2

solved for x
x = 1/2y - 1/2

inverse function changed x to y and y to x
y = 1/2x - 1/2

correct
yes no?
downup

#187 Help Me ! » how to do this? » 2006-10-12 05:00:10

unique
Replies: 1

take the graph of the function
f(x) = (x - 2)^2,
translate it two units to the right, and write the equation of the new graph.
how do i do that?

they gave me two graphs:/

#188 Help Me ! » quadratic formula » 2006-10-12 04:58:08

unique
Replies: 5

use the quadratic formula to find the roots of the equation
3x^3 - 2x + 5 = 0

i did

formula :
       -b +- sqrt (b^2 - 4ac)
x = ----------------------------
               2a

        - (-2) +- sqrt( (-2)^2 - 4(3)(5) )
x = ----------------------------------------
                2(3)

        2 +- sqrt (-4 - 4(15) )
x = ------------------------------
              6

         2 +- sqrt ( -4 - 60)
x = ------------------------------
                6

         2 +- sqrt ( -64 )
x = ---------------------------
               6

now what i do i forgot?dunno

#192 Re: Dark Discussions at Cafe Infinity » Languages; What Are Yours? » 2006-10-12 03:28:53

oh really.
yeah i have been using imageshack very much..to upload graphs and problems such as that. its very useful

#195 Re: Dark Discussions at Cafe Infinity » Languages; What Are Yours? » 2006-10-12 03:20:48

ok to post any image...
i coudlnt copy from my mac to here
so i used this site to upload my image and copy the direct link image ...and tehn i put img the link and img again

and it came up

here is the site
http://www.imageshack.us/

#199 Re: Jokes » funny riddles » 2006-10-12 03:13:21

smile yeah maybe your right

#200 Re: Dark Discussions at Cafe Infinity » Languages; What Are Yours? » 2006-10-12 03:12:04

MathsIsFun wrote:
unique wrote:

...but i took so great pictures..a great photographer if i do say myself.  smile

Please share them. When you click "Post Reply" there is an image upload where you can do several at once.

umm ok i'll be happy to share them....
if the img share tab works for me

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