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ok i know how to solve system of equations but with this one i am having problems !
1) a - b = 1
2) b - 2c = 1
3) 3a - 4c = 7
ok i know that
you have to first
1equation subtract 2equation
and then
2equation plus 3equation
i know that
but you see that in each equation one letter is missing
so how can we
subtract a-b=1 from b-2c=1
is we dont have a or c????
and same goes for the second part
help:/
Desi
Raat Key Rani !
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it cant be this way right?
a - b = 1
- b - 2c = 1 cross out the b's
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a - 2c = 0 ????
Desi
Raat Key Rani !
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Add the first 2 equations together:
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a = 3
so put in the value in the equation:
3a - 4c = 7
3(3) - 4c = 7
9 - 4c = 7
subtract 9 both sides
-4c = -2
divide
c = 0.5 or 1/2 right
then c = 0.5
put in value
b - 2c = 1
b - 2(0.5) = 1
b - 1 = 1
add 1 both sides
b = 2 correct
THANKS
Desi
Raat Key Rani !
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