Math Is Fun Forum

  Discussion about math, puzzles, games and fun.   Useful symbols: ÷ × ½ √ ∞ ≠ ≤ ≥ ≈ ⇒ ± ∈ Δ θ ∴ ∑ ∫ • π ƒ -¹ ² ³ °

You are not logged in.

#226 Re: Exercises » A bullet » 2024-01-10 19:26:26

It seems you forgot to add the initial speed of the bullet.
I guess this speed is also assumed constant (no friction).

#227 Re: Puzzles and Games » Add 13 more and post it forever. » 2024-01-05 20:51:26

My broken calculator knows how to divide.
It knows how to multiply.
But it knows how to add 1 only.

(30,160/13+1)*13 = (2320+1)*13 =30,173

#228 Formulas » Hearing versus Knowing » 2024-01-02 21:37:10

KerimF
Replies: 0

Hearing of a set of formulas is not bad and it could be an important first step.

But only knowing when and how these formulas is useful to solve a problem in an easier and/or faster way lets someone be scientific and professional in certain fields.

In fact, the origin of every formula was the need of a simpler and/or faster way to solve a repeated problem in certain applications.

#229 Re: Help Me ! » Fractions involving a square root » 2023-12-23 11:42:36

You did very well
a+(√5)/(b) = (5+√5)/(5) = 5/5+(√5)/(5) = 1+(√5)/(5)

#230 Re: Help Me ! » 3 (at least) definitions of 'angle' ?!?! » 2023-12-20 02:12:14

For instance, when I was a student in schools then universities, I used to (actually I had to) follow, in every exam, the definitions that pleased the teacher in charge of it.
After graduation, I was able to start a private business as a designer in electronics for the local consumers (I am 74). And since then, I used to follow at work what pleases me only big_smile

#231 Re: Help Me ! » Method for; 3^c=1/ √3 ? » 2023-12-17 14:25:19

3^c = 1 / √3
3^c = 1 / 3^(1/2)
3^c = 3^(-1/2)

c = -1/2

#232 Re: Help Me ! » Method for; 3^b = 9√3 Solve for b? » 2023-12-17 14:23:37

3^b = 9√3
3^b = 3^2 * 3^1/2
3^b = 3^(2+1/2)
3^b = 3^(5/2)

b = 5/2

#233 Re: Help Me ! » What is the method for; 3^a = 1/9 Solve for a. ? » 2023-12-17 14:16:45

Perhaps you mean the following method:

3^a = 1/9
3^a = 1/(3^2)
3^a = 3^(-2)

a= -2

#234 Re: Dark Discussions at Cafe Infinity » Parallelism » 2023-12-16 05:16:23

It seems no one around here recall well the first definition of parallelism he heard of at school tongue It was:
Two straight lines are said parallel if they don’t intersect.
Kids see this wrong definition as being true because they see the geometrical figures on their sheets of paper only or on any other planes.

Only when these kids will grow up and start to see them (geometrical figures) in space, they will know it is wrong and it needs to be updated as:
Two straight lines are said parallel if they don’t intersect and are on the same plane.

As long they will not need to learn the perspective geometry, the second definition is all what they need to know about how parallelism is defined.

But those who will need learning it (the perspective geometry), they will hear the complete definition of parallelism which is:
Two straight lines are said parallel if they do intersect at infinity.

I guess, it is out of question introducing parallelism to kids using its third and best definition, right?

Similarly, introducing the fact of Creation to the kids of humanity, our very old ancestors, by unreal tales was very important at those early times, as the first definition of parallelism is also wrong but important for the kids at elementary school.

So now, I don't need to hear any tale to know that there is a supernatural Will/Power that let me (actually forced me to) exist temporarily in a realm which is defined/limited by time and space. Fortunately, like any other human, I was also given, by design, a human brain in which I used to trust its power to no limit (equivalent to trusting its maker to no limit). It helped me discover, with time, the logical answers to all important/crucial questions, related to my own existence and the real world on earth, which I was looking for.

Kerim

#235 Re: Help Me ! » 3 (at least) definitions of 'angle' ?!?! » 2023-12-16 04:00:52

Your remark is interesting.

As you know, a line is formed by dots (geometrical dots).
And by definition, a geometrical dot has no dimensions; actually, this means that it could be given any dimensions.

To answer your questions (confusion), we can assume that the dimensions of the dots forming the arms and the vertex of an angle are infinitesimal small (close to zero, though they are not in our drawings using a pen). This makes all definitions, you presented, be equivalent to each other, at least in theory (speaking geometry).

#236 Re: Exercises » Transporting fuel_2 » 2023-12-15 10:54:16

By the way, we get the same result (Vb) if:

(Va) = 12600 liters (was 16,800 liters)
AB = 360 miles (was 420 miles)
(Vt) = 4200 liters (as before)
(Ct) = 10 liters/mile (as before)

#237 Re: Euler Avenue » Three dimension maths » 2023-12-15 10:43:17

Very nice thought... j^4 = j^2 * j^2 = (-i) * (-i) = -1
In this case, a 3D complex number could be expressed as: A + Bi + Cj
This could lead us to 4D complex numbers as: A + Bi + Cj +Dk where k^8=-1
and so on...

#238 Re: Help Me ! » Method for cube root 3 * cube root 3 ? » 2023-12-15 10:25:37

Perhaps you mean as:
cube root y * cube root y * cube root y = cube root y^3

For example:
cube root 27 * cube root 27 * cube root 27 = cube root 19683 (which = 27)

#239 Re: Exercises » Transporting fuel_2 » 2023-12-13 20:16:10

I am afraid that this is another exercise whose logical solution is much harder than its numerical one which follows it.
So, even an AI robot cannot solve it, unless its human's programmer had the chance to hear its kind and knew how to solve it in the first place.

#240 Exercises » Transporting fuel_2 » 2023-12-12 01:16:23

KerimF
Replies: 2

About 5 years ago, I posted a similar exercise. New members may like hearing it too. I just changed the given values.

A city (A) has 16,800 liters of fuel (Va) in excess.
A city (B), 420 miles away (AB=420), was in real need of some fuel.
The available transport tank at (A) had a capacity of 4200 liters only (Vt) and it consumes 10 liters per mile (Ct).

Obviously, transporting any amount of fuel in one trip was not possible because AB = Vt/Ct; that is all transported fuel would be consumed in that trip. 
Therefore, if it was possible, as requested, to install fuel reservoirs/stations anywhere between the two cities, what was the maximum quantity of fuel (Vb) that could be delivered at the second city (B)?

[1] 710 liters
[2] 1420 liters
[3] 2130 liters
[4] 2840 liters
[5] 3550 liters

Kerim

#241 Re: Exercises » One Equation with Two Unknowns » 2023-12-10 01:18:14

Bob wrote:

I'd not met zetafunc's method before. As it can be made to simplify any such equation it should always work; although it could lead to 'no solutions' of course.  I'm going to explore it some more.

Bob

You may like to solve for example:
107*A + 109*B = 10,000

#242 Re: Exercises » One Equation with Two Unknowns » 2023-12-09 20:15:45

zetafunc wrote:

Thank you for introducing this method which I am not familiar to.

Its crucial step is to find ‘p’ the inverse of Z (modulo n) which leads us to solve another equation with two unknowns as:
Z*p = n*q + 1 , where ‘p’ and ‘q’ are also natural numbers.

In this exercise it is:
12*p = 17*q + 1

And it is clearly simpler than the original one:
17*A + 29*B = 1000

I wonder if this will be the case always.

Kerim

#244 Re: Exercises » One Equation with Two Unknowns » 2023-12-08 20:55:23

phrontister wrote:

Also, here's a Mathematica formula, with constraints that a & b are positive integers:

It is always good to know how to use a math tool when it is available.
On my side, I see myself fortunate that I can still use Excel (a very old version) to solve various mathematical problems related to my designs (in electronics).

It happens that, since very long, I have no more the privilege, as most engineers in the world have, to download a tool/program, free or paid, for advanced math (besides other CAD) to save time in solving complex math problems. But, to me in the least, this is not bad at all, because I enjoy, since I was young (74-year now) playing with numbers, parameters, variables, formulas and equations. I also used, since after graduation, to write CPU then MCU codes in assembly language only for my various designed controllers (needed by the local consumers in every period of time) because I am also not allowed to download any high language compiler.
Anyway, being a rather old man, I expect losing, gradually with time, the last helper I still have, my human brain smile

About math tools, I recall I purchased a programmable TI calculator while studying for MS degree. It could be programmed to solve non-linear equations. At a final exam, I entered the non-linear equation, somehow complex, related to the given problem and let the calculator find out the answer. The professor didn't expect that a student could find the answer in the limited exam's time. He told me that what I did is like cheating. So, I gave him my calculator and ask him to use it, as I did, and have the answer.
He replied: "But I don't know how to use it". I went on saying: "Me too, I had no idea how to use it. But I spent enough time to learn its various functions to help me save time when necessary. This calculator cannot find out the equation of the problem. It can solve it only". He apologized and gave me the highest grade.

#245 Re: Exercises » One Equation with Two Unknowns » 2023-12-08 03:04:01

Well done, Bob. I liked your method.

On my side, I used Excel. I varied y from 1 to int(1000/29)=34 and found out when (1000-19y)/17 became an integer.

Kerim

#246 Exercises » One Equation with Two Unknowns » 2023-12-07 23:42:52

KerimF
Replies: 10

A librarian needed two different books.
The price of book (A) is $17.
The price of book (B) is $29.
How many books he bought if their total cost was $1000?

Kerim

#247 Dark Discussions at Cafe Infinity » Being and Not Being of This World » 2023-11-30 20:45:25

KerimF
Replies: 0

Being of this world means that a human has no choice but to follow always the preprogrammed instructions embedded in his living flesh, known as instincts, as all other living things do. Some of the human’s preprogrammed instructions are the instincts of survival, superiority, selfishness and applying a certain justice on others.

Therefore, not being of this world means that a human can oppose and even defeat his natural robotic nature. Such a human loves even his enemies, is humble no matter how great he may be, sees other humans as an extension of his being and doesn't apply any justice on others.

Being and not being of this world were first known since about 2000 years ago.

#248 Dark Discussions at Cafe Infinity » Parallelism » 2023-11-30 02:36:06

KerimF
Replies: 1

Hi All,

A natural fact is that knowledge, scientific or else, has to be taught in steps according to age.
I chose ‘parallelism’ to explore it.

I was personally taught parallelism in 3 steps; 3 successive definitions while I grew up.
Definition 1:
If you remember well the first definition you heard of at school when you were little kids (first year of geometry), you can easily fill the gap in the following sentence:
Two straight lines are said parallel if...

I didn’t complete it because I like to know first if we all heard of the same definition at that age. Thank you.

For instance, the end result of this topic is more philosophical than mathematical. It is related to a natural truth that the multitudes around the world are not supposed to hear smile But you will be aware of this hidden truth if you too were able to recall, as I do, the 3 definitions of parallelism we learnt while we grew up (I assume you are older than 20 years).

Kerim

#249 Re: Exercises » A Motion Exercise » 2023-11-29 03:18:26

To those who got the logical step and to complete the exercise, here is the mathematical step:
From the right triangle (SWY ), we can write:

[(S2*T1) + R]^2 = D^2 + (S1*T)^2  ,  //T1 = time from W to X//

(S2*T1)^2 + 2*S2*T1*R + R^2 = D^2 + (S1*T)^2

(S2*T1)^2 + 2*S2*T1*R + R^2 - D^2 - (S1*T)^2 = 0

If T2 = time from X to Y, T2=R/S3
T = T1 + T2
T1 = T – T2
T1 = T – R/S3

By replacing T1:
S2^2*(T – R/S3)^2 + 2*S2*(T – R/S3)*R + R^2 - D^2 - (S1*T)^2 = 0

S2^2*(T^2 – 2*R/S3*T + R^2/S3^2) + 2*S2*(T – R/S3)*R + R^2 - D^2 - (S1*T)^2 = 0

S2^2*T^2 – 2* S2^2*R/S3*T + S2^2*R^2/S3^2 + 2*S2*R*T – 2*S2*R^2/S3 + R^2 - D^2 - S1^2*T^2 = 0

(S2^2 - S1^2)*T^2 – 2* S2*R*(S2/S3 - 1)*T + S2^2*R^2/S3^2 – 2*S2*R^2/S3 + R^2 - D^2 = 0

(S2^2 - S1^2)*T^2 – 2* S2*R*(S2/S3 - 1)*T + R^2*(S2/S3 – 1)^2 - D^2 = 0

This is a quadratic equation whose general parameters (a), (b) and (c) are:
a = S2^2 - S1^2
b= –2* S2*R*(S2/S3 - 1)
c= R^2*(S2/S3 – 1)^2 - D^2

A numeric example:
D = 24.11 km
S1 = 30 km/h
S2 = 45 km/h
S3 = 150 km/h
R = 20 km

The mission time is T = 15 min.

Kerim

#250 Re: Exercises » A Motion Exercise » 2023-11-27 20:19:13

I will refer here to your original diagram (I guess you still have it).

I used to tell my students that, in general, finding how to solve a problem has two main directions, forwards and backwards.
To solve this exercise, walking backwards makes it a simple one.
   
Let us assume first that the full range (R) of the missile was used.
In this case, the warship had to be on the circle whose center is ‘Y’ and radius is (R).
If we draw this circle, it becomes clear that WX is the shortest distance from W to this circle.
Therefore, the mathematical solution of T=f(D,R,S1,S2,S3) could take advantage of Pythagoras theorem of the right triangle SWY.

One may think that it is not necessarily to use the full range of the missile, say (k*R) instead of (R), where 0<k<1.
The same reasoning above also applies in case (k*R). Only the radius of the circle becomes (k*R) instead of (R).
This means that T_new = f(D,k*R,S1,S2,S3). That is (R) is replaced with (k*R) in the final formula of (T).
And by analyzing the variation of the function (T_new) with the variable parameter (k), we will find out that T_new > T for all values of (k).

Board footer

Powered by FluxBB