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Similar to my last post (the question came in 3 parts), I worked this out, eventually, through trial and error, but I’m wondering what the method is.
My trial and error went something like;
9√3 suggested a fractional index
The √3 suggested 2 for the numberator of the fractional index
Then I had to try several values for the denominator before landing on 5, giving b=5/2
So, 3^5/2=9√3
Check; √3√3√3√3√3=√243
√243=√81√3
=9√3
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3^b = 9√3
3^b = 3^2 * 3^1/2
3^b = 3^(2+1/2)
3^b = 3^(5/2)
b = 5/2
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