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Suppose z=(x1x2)^a
where x1, x2, a>0
How can I prove that this function is quasiconcave without assuming differentiability?
I know that the condition when a function is nondifferentiable is:
f(aX0+(1-a)x1)>= min{f(x0),f(x1)}
But Im not sure how to apply it because of the 'a' exponent. Any tips?
Happy Thanksgiving everyone!
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