Math Is Fun Forum

MarkusD

Member

Registered: 2006-10-08

Posts: 28

Question on Quasiconcavity

Suppose z=(x1x2)^a

where x1, x2, a>0

How can I prove that this function is quasiconcave without assuming differentiability?

I know that the condition when a function is nondifferentiable is:

f(aX0+(1-a)x1)>= min{f(x0),f(x1)}

But Im not sure how to apply it because of the 'a' exponent. Any tips?

Happy Thanksgiving everyone!