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I have a question:
If a/b=c/d (implying ad=bd), then how does a/b=c/d= (a+c)/(b+d)? Can someone verify this?
Last edited by MarkusD (2007-11-03 13:50:55)
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Another way of doing it
as implied ad=bc
also b=ad/c and d=bc/a
a+c/b+d=>a+c/(ad/c)+d
=>a+c/d(a+c/c)
or ((a+c)*c)/(d*(a+c))
cancel the numerator and the denominator., the outcome is a+c/b+d=c/d
now repeat the same exercise by substituting d=bc/a
a+c/b+d=>(a+c)/(b+bc/a)
=>(a+c)*a/b*(a+c)
cancel the numerator and the denominator., the outcome is a+c/b+d=a/b
hence a/b=c/d=a+b/c+d
regards
khushboo
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Last edited by JaneFairfax (2007-11-04 22:11:10)
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