Math Is Fun Forum

MarkusD

Member

Registered: 2006-10-08

Posts: 28

Equal Fractions

I have a question:

If a/b=c/d (implying ad=bd), then how does a/b=c/d= (a+c)/(b+d)? Can someone verify this?

Last edited by MarkusD (2007-11-03 13:50:55)

Identity

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Registered: 2007-04-18

Posts: 934

Re: Equal Fractions

Khushboo

Member

Registered: 2007-10-16

Posts: 47

Re: Equal Fractions

Another way of doing it

as implied ad=bc

also b=ad/c and d=bc/a

a+c/b+d=>a+c/(ad/c)+d
            =>a+c/d(a+c/c)
    or ((a+c)*c)/(d*(a+c))
    cancel the numerator and the denominator., the outcome is a+c/b+d=c/d

now repeat the same exercise by substituting d=bc/a
a+c/b+d=>(a+c)/(b+bc/a)
            =>(a+c)*a/b*(a+c)
cancel the numerator and the denominator., the outcome is a+c/b+d=a/b

hence a/b=c/d=a+b/c+d

regards
khushboo

JaneFairfax

Member

Registered: 2007-02-23

Posts: 6,868

Re: Equal Fractions

Last edited by JaneFairfax (2007-11-04 22:11:10)