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How do I draw this on a graph and state the domain + range?
- ( 2 x<-2
- f(x) = < √4-x² -2≤x≤2
- ( -|x| x>2
NOTE: √4-x² all of that is square rooted (i.e. <start square rooting> 4-x² </stop rooting>
Thanks in advance
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When you have functions that split up like that, you just need to draw all the pieces, as if they were three seperate graphs.
For x<-2, it's a constant function of 2.
For -2≤x≤2, it's √ (4-x²), which is a negative quadratic.
For x>2, it's -|x| (which in this case is the same as -x) and so you'd draw a downward sloping line.
The function is defined for all reals, so its domain is the reals, and its range is reals that are ≤ 2.
Why did the vector cross the road?
It wanted to be normal.
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