Math Is Fun Forum

  Discussion about math, puzzles, games and fun.   Useful symbols: ÷ × ½ √ ∞ ≠ ≤ ≥ ≈ ⇒ ± ∈ Δ θ ∴ ∑ ∫ • π ƒ -¹ ² ³ °

You are not logged in.

#1 2007-08-06 22:05:00

12334545
Member
Registered: 2007-04-02
Posts: 5

Scetch and find domain + range

How do I draw this on a graph and state the domain + range?

-                 (  2                         x<-2
-      f(x) = <  √4-x²                  -2≤x≤2
-                 (  -|x|                     x>2

NOTE: √4-x² all of that is square rooted (i.e. <start square rooting> 4-x² </stop rooting>

Thanks in advance

Offline

#2 2007-08-06 22:19:13

mathsyperson
Moderator
Registered: 2005-06-22
Posts: 4,900

Re: Scetch and find domain + range

When you have functions that split up like that, you just need to draw all the pieces, as if they were three seperate graphs.

For x<-2, it's a constant function of 2.
For -2≤x≤2, it's √ (4-x²), which is a negative quadratic.
For x>2, it's -|x| (which in this case is the same as -x) and so you'd draw a downward sloping line.

The function is defined for all reals, so its domain is the reals, and its range is reals that are ≤ 2.


Why did the vector cross the road?
It wanted to be normal.

Offline

Board footer

Powered by FluxBB