Discussion about math, puzzles, games and fun. Useful symbols: ÷ × ½ √ ∞ ≠ ≤ ≥ ≈ ⇒ ± ∈ Δ θ ∴ ∑ ∫ π -¹ ² ³ °

You are not logged in.

- Topics: Active | Unanswered

Pages: **1**

**websitedeveloper****Member**- Registered: 2005-03-12
- Posts: 2

Show that there are no rational numbers 2x^2 - 3y^2 = 1 but that there are infinitely many rationals x, and y such that 2x^2 - 3y^2 = -1.

Can anyone provide me an answer within 24 hours of post of this question.Help would be highly appreciated.

Thank you.

Offline

**MathsIsFun****Administrator**- Registered: 2005-01-21
- Posts: 7,664

Luckily, this has been done already here

"The physicists defer only to mathematicians, and the mathematicians defer only to God ..." - Leon M. Lederman

Offline

**websitedeveloper****Member**- Registered: 2005-03-12
- Posts: 2

Hi,

Oh thank you admin!!! thank you so much.. your reply has been so helpful..i really appreciate your help... thanks a lot man.. you really made my life easier.. thank you.....oh.. you do not have any idea how happy you made me... God bless you man... really, i mean it.. and can you tell me where & how you exactly got the answer from???

thanks a lot once again...

*Last edited by websitedeveloper (2005-03-13 21:41:18)*

Offline

Pages: **1**