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**websitedeveloper****Member**- Registered: 2005-03-12
- Posts: 2

Show that there are no rational numbers 2x^2 - 3y^2 = 1 but that there are infinitely many rationals x, and y such that 2x^2 - 3y^2 = -1.

Can anyone provide me an answer within 24 hours of post of this question.Help would be highly appreciated.

Thank you.

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**MathsIsFun****Administrator**- Registered: 2005-01-21
- Posts: 7,630

Luckily, this has been done already here

"The physicists defer only to mathematicians, and the mathematicians defer only to God ..." - Leon M. Lederman

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**websitedeveloper****Member**- Registered: 2005-03-12
- Posts: 2

Hi,

Oh thank you admin!!! thank you so much.. your reply has been so helpful..i really appreciate your help... thanks a lot man.. you really made my life easier.. thank you.....oh.. you do not have any idea how happy you made me... God bless you man... really, i mean it.. and can you tell me where & how you exactly got the answer from???

thanks a lot once again...

*Last edited by websitedeveloper (2005-03-13 21:41:18)*

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