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#151 2006-12-06 06:07:21

Ehiness
Member
Registered: 2006-12-05
Posts: 6

Re: 0.9999....(recurring) = 1?

Altough

is not a number and it is impossible to count to infinity, 0.9(1 second) 0.99(2 seconds) 0.999(3 seconds)
seconds)

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#152 2006-12-06 06:14:42

numen
Member
Registered: 2006-05-03
Posts: 115

Re: 0.9999....(recurring) = 1?

Anthony, take a look at this:

   1.00000000...
-  0.99999999...
= 0.00000000...

Since the number of zero's is infinite, it is the same as writing 0 as there can't be anything after the infinitely many zero's (just as 1.000... is the same as 1, or 5.5999... = 5.6). Thus, there is no difference between 1 and 0.999... they are the same thing!

As pointed out already, there is no such thing as 0.0000...1. The only thing it proofs is that you don't understand the concept of infinity.

If you still don't believe it, prove us wrong. Otherwise none will take you seriously.


Bang postponed. Not big enough. Reboot.

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#153 2006-12-06 07:43:59

Ricky
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Registered: 2005-12-04
Posts: 3,791

Re: 0.9999....(recurring) = 1?

Actually, it's not so much of the concept of infinity that is incorrect.  Anthony continues to state that 0.999... somehow grows.  How real numbers grow, well, you got me.


"In the real world, this would be a problem.  But in mathematics, we can just define a place where this problem doesn't exist.  So we'll go ahead and do that now..."

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#154 2006-12-06 10:07:36

MathsIsFun
Administrator
Registered: 2005-01-21
Posts: 7,551

Re: 0.9999....(recurring) = 1?

I must write a page on infinity.

I am thinking of starting:

"Infinity is not a big number, it is not a HUGE number, it is not a GINORMOUS number, in fact it is not even a number ... it is a CONCEPT of something without end."


"The physicists defer only to mathematicians, and the mathematicians defer only to God ..."  - Leon M. Lederman

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#155 2006-12-06 12:03:51

Ricky
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Registered: 2005-12-04
Posts: 3,791

Re: 0.9999....(recurring) = 1?

"Infinity is not a big number, it is not a HUGE number, it is not a GINORMOUS number, in fact it is not even a number ... it is a CONCEPT of something without end."

Even that ain't always true.  But it is for the reals.

One important thing to address is the idea of different types of infinities.  I saw an argument which was taken much off of Cantor's diagonal proof, but much simpler.  Let me see if I can find it again...


"In the real world, this would be a problem.  But in mathematics, we can just define a place where this problem doesn't exist.  So we'll go ahead and do that now..."

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#156 2006-12-09 02:53:44

Anthony.R.Brown
Banned
Registered: 2006-11-16
Posts: 516

Re: 0.9999....(recurring) = 1?

So there we have it! A simple counter Proof to any Proof put forward so far,that says Infintite 0.9 = 1

Unless someone can actually say how many .9’s there are! Or it takes for Infinite 0.9 to be! Or to equal 1,then its impossible for them to say they have a Proof!
But if someone has found the number Please insert your number in the Brackets below!

Infinite 0.9 ( How many .9’s  there are! Or it takes to = ) 1 ?

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#157 2006-12-09 04:20:38

simron
Real Member
Registered: 2006-10-07
Posts: 237

Re: 0.9999....(recurring) = 1?

So I guess that the official notation for this would be
lim(.999...)=1
Tell me if I am using the limit wrongly.


Linux FTW

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#158 2006-12-09 05:27:14

Ehiness
Member
Registered: 2006-12-05
Posts: 6

Re: 0.9999....(recurring) = 1?

Anthony.R.Brown wrote:

So there we have it! A simple counter Proof to any Proof put forward so far,that says Infintite 0.9 = 1
Unless someone can actually say how many .9’s there are! Or it takes for Infinite 0.9 to be! Or to equal 1,then its impossible for them to say they have a Proof!

That is not a counter proof, that is just being stubborn.

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#159 2006-12-10 02:26:42

Anthony.R.Brown
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Registered: 2006-11-16
Posts: 516

Re: 0.9999....(recurring) = 1?

QUOTE:
simron
Member
Re: 0.9999....(recurring) = 1So I guess that the official notation for this would be
lim(.999...)=1
Tell me if I am using the limit wrongly.

Hi! simron! or should that be "stillwrong" just to let you know! you are still wrong,

it should be Endless(.999...)<>1 because no one knows  How many .9’s  there are! Or it takes to = ) 1 ? ie so far no limit!!


--------------------------------------------------------------------------------

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#160 2006-12-10 04:23:13

vipaman
Member
Registered: 2006-09-30
Posts: 22

Re: 0.9999....(recurring) = 1?

nice

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#161 2006-12-10 05:42:25

luca-deltodesco
Member
Registered: 2006-05-05
Posts: 1,470

Re: 0.9999....(recurring) = 1?

you really aernt getting this are you anthony, this really is like talking to a brick wall?


The Beginning Of All Things To End.
The End Of All Things To Come.

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#162 2006-12-10 06:17:12

Ricky
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Registered: 2005-12-04
Posts: 3,791

Re: 0.9999....(recurring) = 1?

Maybe we should try this step by step.

Anthony,  what is the result when you divide 1 by 3, in decimals?

Please let Anthony answer.


"In the real world, this would be a problem.  But in mathematics, we can just define a place where this problem doesn't exist.  So we'll go ahead and do that now..."

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#163 2006-12-11 01:53:00

Anthony.R.Brown
Banned
Registered: 2006-11-16
Posts: 516

Re: 0.9999....(recurring) = 1?

To luca-deltodesco

Quote:"you really aernt getting this are you anthony, this really is like talking to a brick wall?"

The Brick wall argument has already been tried!!

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#164 2006-12-11 02:01:09

Anthony.R.Brown
Banned
Registered: 2006-11-16
Posts: 516

Re: 0.9999....(recurring) = 1?

To Ricky

Quote: "Anthony,  what is the result when you divide 1 by 3, in decimals?"

Erh! I reckon the true Answer has an Infinite number of Decimal Places!!

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#165 2006-12-11 02:18:14

Ricky
Moderator
Registered: 2005-12-04
Posts: 3,791

Re: 0.9999....(recurring) = 1?

Well, now its obvious that Anthony is just trolling.  Asking the same questions over an over again, not listening to answers, and never even attempting to answer our questions.


"In the real world, this would be a problem.  But in mathematics, we can just define a place where this problem doesn't exist.  So we'll go ahead and do that now..."

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#166 2006-12-11 02:24:44

Anthony.R.Brown
Banned
Registered: 2006-11-16
Posts: 516

Re: 0.9999....(recurring) = 1?

To Ricky!

I asked the Question first!!

Infinite 0.9 ( How many .9’s  there are! Or it takes to = ) 1 ?

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#167 2006-12-11 03:50:55

Ricky
Moderator
Registered: 2005-12-04
Posts: 3,791

Re: 0.9999....(recurring) = 1?

Does that mean you refuse to answer any questions I ask on the topic?

Sorry, but if you won't extend me the courtesy of answering my questions, why should I do so to you?  Besides, I have already tried.


"In the real world, this would be a problem.  But in mathematics, we can just define a place where this problem doesn't exist.  So we'll go ahead and do that now..."

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#168 2006-12-11 05:06:59

Patrick
Real Member
Registered: 2006-02-24
Posts: 1,005

Re: 0.9999....(recurring) = 1?

Anthony you are beyond reach man. Ricky is trying to explain why your answer can't be answered(because it simply doesn't make sense) by asking you a question in return.


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#169 2006-12-11 07:14:15

Devantè
Real Member
Registered: 2006-07-14
Posts: 6,400

Re: 0.9999....(recurring) = 1?

Anthony.R.Brown. A living conspiracy.

?

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#170 2006-12-12 01:36:14

Anthony.R.Brown
Banned
Registered: 2006-11-16
Posts: 516

Re: 0.9999....(recurring) = 1?

To Ricky!

Ok lets do this 1/3 = Infinite 0.33333333333333333333...................

Agreed! and....Infinite 0.9 = 0.99999999999999999999................... which you say = 1 

So if you are correct then Infinite 0.3333333333333333.................. must = > 0.3

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#171 2006-12-12 05:12:34

Ricky
Moderator
Registered: 2005-12-04
Posts: 3,791

Re: 0.9999....(recurring) = 1?

Ok lets do this 1/3 = Infinite 0.33333333333333333333...................

What happens when you multiply both sides by 3?


"In the real world, this would be a problem.  But in mathematics, we can just define a place where this problem doesn't exist.  So we'll go ahead and do that now..."

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#172 2006-12-12 05:43:29

Patrick
Real Member
Registered: 2006-02-24
Posts: 1,005

Re: 0.9999....(recurring) = 1?

Anthony.R.Brown wrote:

To Ricky!

Ok lets do this 1/3 = Infinite 0.33333333333333333333...................

Agreed! and....Infinite 0.9 = 0.99999999999999999999................... which you say = 1 

So if you are correct then Infinite 0.3333333333333333.................. must = > 0.3

What kinda of logic are you applying here? I could understand you, if we were saying that 0.99... = 0.9 but we're not


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#173 2006-12-12 19:46:27

Devantè
Real Member
Registered: 2006-07-14
Posts: 6,400

Re: 0.9999....(recurring) = 1?

0.3 ≠ [sup]1[/sup]/[sub]3[/sub]

Last edited by Devanté (2006-12-12 19:46:42)

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#174 2006-12-13 02:25:18

Anthony.R.Brown
Banned
Registered: 2006-11-16
Posts: 516

Re: 0.9999....(recurring) = 1?

To Ricky! again I asked the Question first!!

To Ricky!

Ok lets do this 1/3 = Infinite 0.33333333333333333333...................

Agreed! and....Infinite 0.9 = 0.99999999999999999999................... which you say = 1 

So if you are correct then Infinite 0.3333333333333333.................. must = > 0.3

Incase you dont understand the Above!

If one Infinite number,is or becomes another number from the number it started as! ie Infinite 0.9 (stage one) becomes or is some how equal to 1 ?
then surley using your Logic! all Infinte numbers! ie Infinite 0.3 (stage one) must also do the same!!

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#175 2006-12-13 02:52:10

Anthony.R.Brown
Banned
Registered: 2006-11-16
Posts: 516

Re: 0.9999....(recurring) = 1?

If you like this one!! then have a look at this new thread!

FLT DEMONSTRATION By Anthony.R.Brown

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