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I can't work out the derivative for this equation;P = 2t³/3 + t² - 40t - 5and then i need to find what 't' is when the derivative of the above equation = 0.Any help would be great.Thanks!
and ofcourseif f(x) = a0(x) + a1(x) ... an(x);f'(x) = a0'(x) + a1'(x) .... an'(x);soP(t) = 2t³/3 + t² - 40t - 5P'(t) = 2t² + 2t - 40 = 0, 2(t+½)² = 40½, (t+½)^2 = 20¼, t = -½ ± √(20¼) = -½ ± 4½, t = 4, t = -5
Last edited by luca-deltodesco (2006-08-23 06:08:39)
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