I can't work out the derivative for this equation;
P = 2t³/3 + t² - 40t - 5
and then i need to find what 't' is when the derivative of the above equation = 0.
Any help would be great.
The left side is your derivative. Does this help or should I give you some hints?
When you've got the derivative, set it equal to 0 to obtain your equation, then solve for t.
Bang postponed. Not big enough. Reboot.
if f(x) = a0(x) + a1(x) ... an(x);
f'(x) = a0'(x) + a1'(x) .... an'(x);
P(t) = 2t³/3 + t² - 40t - 5
P'(t) = 2t² + 2t - 40 = 0, 2(t+½)² = 40½, (t+½)^2 = 20¼, t = -½ ± √(20¼) = -½ ± 4½, t = 4, t = -5
Last edited by luca-deltodesco (2006-08-22 08:08:39)
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