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#1 2006-08-21 23:50:30

Titus
Member
Registered: 2005-03-07
Posts: 10

Derivatives

I can't work out the derivative for this equation;

P = 2t³/3 + t² - 40t - 5

and then i need to find what 't' is when the derivative of the above equation = 0.

Any help would be great.
Thanks!

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#2 2006-08-22 02:28:23

numen
Member
Registered: 2006-05-03
Posts: 115

Re: Derivatives

Generally speaking,

The left side is your derivative. Does this help or should I give you some hints?
When you've got the derivative, set it equal to 0 to obtain your equation, then solve for t.


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#3 2006-08-22 08:07:46

luca-deltodesco
Member
Registered: 2006-05-05
Posts: 1,470

Re: Derivatives

and ofcourse
if f(x) = a0(x) + a1(x) ... an(x);
f'(x) = a0'(x) + a1'(x) .... an'(x);

so

P(t) = 2t³/3 + t² - 40t - 5
P'(t) = 2t² + 2t - 40 = 0, 2(t+½)² = 40½, (t+½)^2 = 20¼, t = -½ ± √(20¼) = -½ ± 4½, t = 4, t = -5

Last edited by luca-deltodesco (2006-08-22 08:08:39)


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