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## #1 2006-08-20 00:13:49

mgca
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### Where does the 'm' come from in y=mx+c

In y=mx+c, I  know that 'm' stands for the gradient of the straight line and the 'c' stands for the y intercept, but why 'm' and 'c'???

I have heard it suggested that 'm' stands for something like 'midron' (meaning gradient) in Hebrew but ?????

And the 'c' .... interCept ??

Any suggestions??

## #2 2006-08-22 05:01:00

Devantè
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### Re: Where does the 'm' come from in y=mx+c

Welcome to MathsIsFun, mgca. However, this is the wrong place to discuss this...

## #3 2006-08-22 05:07:19

mathsyperson
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### Re: Where does the 'm' come from in y=mx+c

Moveded.

As for the question, I'm afraid I have no idea. It's possible that it doesn't come from anywhere, and they just called it m because they had to call it something.

Why did the vector cross the road?
It wanted to be normal.

## #4 2006-08-22 05:17:29

krassi_holmz
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### Re: Where does the 'm' come from in y=mx+c

m may be connected with "multiply" or something
And c is something as constant-it is used very much in calculus it means a free-of-unknowns addend, i think.

IPBLE:  Increasing Performance By Lowering Expectations.

## #5 2006-08-22 09:36:10

Zhylliolom
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### Re: Where does the 'm' come from in y=mx+c

The m comes from MathIsFun.

## #6 2006-08-22 15:32:19

krassi_holmz
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### Re: Where does the 'm' come from in y=mx+c

#### Zhylliolom wrote:

The m comes from MathIsFun.

Right Z

IPBLE:  Increasing Performance By Lowering Expectations.

## #7 2006-08-22 16:33:37

MathsIsFun

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### Re: Where does the 'm' come from in y=mx+c

Naturally!

Here's something: http://www.math.duke.edu/education/webfeats/Slope/Slopederiv.html

"The physicists defer only to mathematicians, and the mathematicians defer only to God ..."  - Leon M. Lederman