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## #1 2006-08-11 22:20:47

Member
Registered: 2006-08-11
Posts: 2

### need help on a simple log question

Hi i am doing a buiolding surveying degree and have come across this log question that im stuck on as i havnt come across them before. If someone could help me out that would be great. Iv got to work out T in each case.

53=10 log (1/T)
log 1/T = 5.3
1/T=

25=10 log (1/T)
log 1/T = 2.5
1/T=

20=10 log (1/T)
log 1/T = 2
1/T=

Thanks for any help

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## #2 2006-08-11 23:32:47

fusilli_jerry89
Member
Registered: 2006-06-23
Posts: 86

### Re: need help on a simple log question

53=10 log (1/T)
log 1/T = 5.3
10^5.3=1/T
199526.2315=1/T
T=5.011872336 x10^-6

25=10 log (1/T)
log 1/T = 2.5
10^2.5=1/T
316.227766=1/T
T=0.0031622777

20=10 log (1/T)
log 1/T = 2
100=1/T
T=0.01

or of the numerators meant bases:

53=10 log (1/T)
log 1/T = 5.3
log T/Log 1=5.3
log 1 = 0;denominators can't be zero(same for all)

or if the denominators meant bases:

53=10 log (1/T)
log 1/T = 5.3
log 1/log T = 5.3
log 1=0
0/log T=5.3
there is no answer in this case

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