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**m_reading****Member**- Registered: 2006-08-11
- Posts: 2

Hi i am doing a buiolding surveying degree and have come across this log question that im stuck on as i havnt come across them before. If someone could help me out that would be great. Iv got to work out T in each case.

53=10 log (1/T)

log 1/T = 5.3

1/T=

25=10 log (1/T)

log 1/T = 2.5

1/T=

20=10 log (1/T)

log 1/T = 2

1/T=

Thanks for any help

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**fusilli_jerry89****Member**- Registered: 2006-06-23
- Posts: 86

53=10 log (1/T)

log 1/T = 5.3

10^5.3=1/T

199526.2315=1/T

T=5.011872336 x10^-6

25=10 log (1/T)

log 1/T = 2.5

10^2.5=1/T

316.227766=1/T

T=0.0031622777

20=10 log (1/T)

log 1/T = 2

100=1/T

T=0.01

or of the numerators meant bases:

53=10 log (1/T)

log 1/T = 5.3

log T/Log 1=5.3

log 1 = 0;denominators can't be zero(same for all)

or if the denominators meant bases:

53=10 log (1/T)

log 1/T = 5.3

log 1/log T = 5.3

log 1=0

0/log T=5.3

there is no answer in this case

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**m_reading****Member**- Registered: 2006-08-11
- Posts: 2

thanks very much for the help its greatly appreciated

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