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I see you have graph paper.
You must be plotting something![]()
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Are you meant to solve it?
Here lies the reader who will never open this book. He is forever dead.
Taking a new step, uttering a new word, is what people fear most. ― Fyodor Dostoyevsky, Crime and Punishment
The knowledge of some things as a function of age is a delta function.
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Yes
I see you have graph paper.
You must be plotting something![]()
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Bump
I see you have graph paper.
You must be plotting something![]()
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No solution.

Bassaricyon neblina
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Here's an algebraic proof. For all x,
[list=*]
[*]
Last edited by Olinguito (2015-03-30 23:43:57)
Bassaricyon neblina
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hi Olinguito
Graph. Excellent idea. But I'm puzzled about that proof. What am I missing?
OK, I like that.
Eh? x = 2.5 => (FLOOR(x^2)+5)/4 = 2.75 yet x^2 + 1 = 7.25
Bob
Children are not defined by school ...........The Fonz
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you! …………….Bob ![]()
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Oops, I did it wrong. ![]()
Back to the drawing board.
Bassaricyon neblina
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Okay, this should work. For all x,
[list=*]
[*]
Also, for all x,
[list=*]
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(Fractional parts cannot be neagative.)
for all x.Is this better, Bob? ![]()
Last edited by Olinguito (2015-03-31 20:04:37)
Bassaricyon neblina
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hi Olinguito
Yes; that looks good to me.
Strictly, as you have one thing ≥ x and another ≥ 0, when you add them you get (one thing + another) ≥ x
But that is easily remedied.
Equality occurs at x = 2, so check what happens there.
(floor(2^2)+5)/4 = (4+5)/4 = 2.25. So this is the closest you can get to the graphs crossing. This shows it:

Thanks for the answer. One wonders why the question was set like this.
Bob
Children are not defined by school ...........The Fonz
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you! …………….Bob ![]()
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Strictly, as you have one thing ≥ x and another ≥ 0, when you add them you get (one thing + another) ≥ x
No, I have the first thing > x and the other ≥ 0.
Last edited by Olinguito (2015-03-31 04:20:59)
Bassaricyon neblina
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Oh yes. Didn't spot that. You're right.
Apologies.
I'm 'ticking' myself off here.
Bob
Children are not defined by school ...........The Fonz
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you! …………….Bob ![]()
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Why did you guys remove {x}
How do u solve this?
I see you have graph paper.
You must be plotting something![]()
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hi cooljackiec,
{x} = x^2 - floor(x^2), so it has not been lost. This is simply a way to graph the left hand side of the equation using available functions.
{fractional part} = <whole> minus <integer part>.
Olinguito has shown that you cannot find values of x to fit this equation. The solution is "no values".
Bob
Children are not defined by school ...........The Fonz
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you! …………….Bob ![]()
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Why did you guys remove {x}
Sorry, it was a typo. I've put it back in post #9.
Last edited by Olinguito (2015-03-31 20:09:15)
Bassaricyon neblina
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