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#1 2006-04-10 00:12:20

RauLiTo
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in the circle

get A and B which make ( AX + BY ) = X (4 Y - 3 X ) + 1 an equation for a circle and then get the centre and the radius .


help please


ImPo$$!BLe = NoTH!nG
Go DowN DeeP iNTo aNyTHinG U WiLL FinD MaTHeMaTiCs ...

#2 2006-04-10 02:07:53

George,Y
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Re: in the circle

AX+2ABXY+BY=4XY-3X+1
(A+3)X+(2AB-4)XY+BY=1

∴2AB-4=0 AND A+3=B AND CENTER IS (0,0)
X/P+Y/P=1 WHERE 1/P=A+3=B
X+Y=P SO THE RADIUS IS P

A=2/B, 4/B+3=B=DEF=X
4/X+3=X

you can go on from here


X'(y-Xβ)=0

#3 2006-04-10 05:47:13

RauLiTo
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Re: in the circle

excuse me can you finish it please ?
it sometimes seems difficult for me to translate that to arabic u know ... sorry everybody for botering cool


ImPo$$!BLe = NoTH!nG
Go DowN DeeP iNTo aNyTHinG U WiLL FinD MaTHeMaTiCs ...

#4 2006-04-10 11:23:25

George,Y
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Re: in the circle

4/X+3=X
4+3X=X
(X-4)(X+1)=0
X=4 and radius r=√x=2
center is O, (0,0)


X'(y-Xβ)=0

#5 2006-04-10 16:20:18

RauLiTo
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Re: in the circle

thanks man wink


ImPo$$!BLe = NoTH!nG
Go DowN DeeP iNTo aNyTHinG U WiLL FinD MaTHeMaTiCs ...

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