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## #1 2006-04-10 00:12:20

RauLiTo
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### in the circle

get A and B which make ( AX + BY ) ² = X (4 Y - 3 X ) + 1 an equation for a circle and then get the centre and the radius .

help please

ImPo\$\$!BLe = NoTH!nG
Go DowN DeeP iNTo aNyTHinG U WiLL FinD MaTHeMaTiCs ...

## #2 2006-04-10 02:07:53

George,Y
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### Re: in the circle

A²X²+2ABXY+B²Y²=4XY-3X²+1
(A²+3)X²+(2AB-4)XY+B²Y²=1

∴2AB-4=0 AND A²+3=B² AND CENTER IS (0,0)
X²/P²+Y²/P²=1 WHERE 1/P²=A²+3=B²
X²+Y²=P² SO THE RADIUS IS P

A=2/B, 4/B²+3=B²=DEF=X
4/X+3=X

you can go on from here

X'(y-Xβ)=0

## #3 2006-04-10 05:47:13

RauLiTo
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### Re: in the circle

excuse me can you finish it please ?
it sometimes seems difficult for me to translate that to arabic u know ... sorry everybody for botering

ImPo\$\$!BLe = NoTH!nG
Go DowN DeeP iNTo aNyTHinG U WiLL FinD MaTHeMaTiCs ...

## #4 2006-04-10 11:23:25

George,Y
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### Re: in the circle

4/X+3=X
4+3X=X²
(X-4)(X+1)=0
X=4 and radius r=√x=2
center is O, (0,0)

X'(y-Xβ)=0

## #5 2006-04-10 16:20:18

RauLiTo
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### Re: in the circle

thanks man

ImPo\$\$!BLe = NoTH!nG
Go DowN DeeP iNTo aNyTHinG U WiLL FinD MaTHeMaTiCs ...

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