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**RauLiTo****Member**- Registered: 2006-01-11
- Posts: 142

get A and B which make ( AX + BY ) ² = X (4 Y - 3 X ) + 1 an equation for a circle and then get the centre and the radius .

help please

ImPo$$!BLe = NoTH!nG

Go DowN DeeP iNTo aNyTHinG U WiLL FinD MaTHeMaTiCs ...

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**George,Y****Member**- Registered: 2006-03-12
- Posts: 1,306

A²X²+2ABXY+B²Y²=4XY-3X²+1

(A²+3)X²+(2AB-4)XY+B²Y²=1

∴2AB-4=0 AND A²+3=B² AND CENTER IS (0,0)

X²/P²+Y²/P²=1 WHERE 1/P²=A²+3=B²

X²+Y²=P² SO THE RADIUS IS P

A=2/B, 4/B²+3=B²=DEF=X

4/X+3=X

you can go on from here

**X'(y-Xβ)=0**

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**RauLiTo****Member**- Registered: 2006-01-11
- Posts: 142

excuse me can you finish it please ?

it sometimes seems difficult for me to translate that to arabic u know ... sorry everybody for botering

ImPo$$!BLe = NoTH!nG

Go DowN DeeP iNTo aNyTHinG U WiLL FinD MaTHeMaTiCs ...

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**George,Y****Member**- Registered: 2006-03-12
- Posts: 1,306

4/X+3=X

4+3X=X²

(X-4)(X+1)=0

X=4 and radius r=√x=2

center is O, (0,0)

**X'(y-Xβ)=0**

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**RauLiTo****Member**- Registered: 2006-01-11
- Posts: 142

thanks man

ImPo$$!BLe = NoTH!nG

Go DowN DeeP iNTo aNyTHinG U WiLL FinD MaTHeMaTiCs ...

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