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#1 2006-04-09 02:12:20

RauLiTo
Member
Registered: 2006-01-11
Posts: 142

in the circle

get A and B which make ( AX + BY ) ² = X (4 Y - 3 X ) + 1 an equation for a circle and then get the centre and the radius .


help please


ImPo$$!BLe = NoTH!nG
Go DowN DeeP iNTo aNyTHinG U WiLL FinD MaTHeMaTiCs ...

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#2 2006-04-09 04:07:53

George,Y
Member
Registered: 2006-03-12
Posts: 1,306

Re: in the circle

A²X²+2ABXY+B²Y²=4XY-3X²+1
(A²+3)X²+(2AB-4)XY+B²Y²=1

∴2AB-4=0 AND A²+3=B² AND CENTER IS (0,0)
X²/P²+Y²/P²=1 WHERE 1/P²=A²+3=B²
X²+Y²=P² SO THE RADIUS IS P

A=2/B, 4/B²+3=B²=DEF=X
4/X+3=X

you can go on from here


X'(y-Xβ)=0

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#3 2006-04-09 07:47:13

RauLiTo
Member
Registered: 2006-01-11
Posts: 142

Re: in the circle

excuse me can you finish it please ?
it sometimes seems difficult for me to translate that to arabic u know ... sorry everybody for botering cool


ImPo$$!BLe = NoTH!nG
Go DowN DeeP iNTo aNyTHinG U WiLL FinD MaTHeMaTiCs ...

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#4 2006-04-09 13:23:25

George,Y
Member
Registered: 2006-03-12
Posts: 1,306

Re: in the circle

4/X+3=X
4+3X=X²
(X-4)(X+1)=0
X=4 and radius r=√x=2
center is O, (0,0)


X'(y-Xβ)=0

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#5 2006-04-09 18:20:18

RauLiTo
Member
Registered: 2006-01-11
Posts: 142

Re: in the circle

thanks man wink


ImPo$$!BLe = NoTH!nG
Go DowN DeeP iNTo aNyTHinG U WiLL FinD MaTHeMaTiCs ...

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