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#1 2006-04-08 04:09:44

razor
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proof

we have function g,in Real numbers dimension m and value p (with p=(p1,...,pm)) is positive.
For at least one p,that g(p)>zero  or equal to zero or g(p)<zero or equal to zero,is true.Also,p*g(p)=0 for p positive.

Then,proof that g(p)=0.

Last edited by razor (2006-04-08 04:19:30)

#2 2006-04-08 18:12:20

George,Y
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Re: proof

at least one p,that g(p)>zero  or equal to zero or g(p)<zero or equal to zero,is true. --do you mean g(p) cannot be (-1,8,...)type?
g is a vector function?
at least one-- i can't use this special condition, lol


X'(y-Xβ)=0

#3 2006-04-09 02:50:15

razor
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Re: proof

g is a vector function and g(p)>=0 or g(p)<=0.

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