Discussion about math, puzzles, games and fun. Useful symbols: ÷ × ½ √ ∞ ≠ ≤ ≥ ≈ ⇒ ± ∈ Δ θ ∴ ∑ ∫ π -¹ ² ³ °

You are not logged in.

- Topics: Active | Unanswered

**razor****Member**- Registered: 2006-02-24
- Posts: 6

we have function g,in Real numbers dimension m and value p (with p=(p1,...,pm)) is positive.

For at least one p,that g(p)>zero or equal to zero or g(p)<zero or equal to zero,is true.Also,p*g(p)=0 for p positive.

Then,proof that g(p)=0.

*Last edited by razor (2006-04-07 06:19:30)*

Offline

**George,Y****Member**- Registered: 2006-03-12
- Posts: 1,315

at least one p,that g(p)>zero or equal to zero or g(p)<zero or equal to zero,is true. --do you mean g(p) cannot be (-1,8,...)type?

g is a vector function?

at least one-- i can't use this special condition, lol

**X'(y-Xβ)=0**

Offline

**razor****Member**- Registered: 2006-02-24
- Posts: 6

g is a vector function and g(p)>=0 or g(p)<=0.

Offline