You are not logged in.

- Topics: Active | Unanswered

Pages: **1**

Hey all,

I decided to create a math quizzes that everyone on the forum can answer.

1) Let ABCD be a parallelogram where E is a point between AB such that 3BE = 2DC The lines CE and BD intersect at the point Q. If the area of <DQC is 36. Find the area of <BQE.

More to come...

It's not how good you are. It's how good you want to be - Paul Arden

Offline

**ElainaVW****Member**- Registered: 2013-04-29
- Posts: 270

Hello:

Offline

**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 81,656

Hi;

I have the result, but I do not yet know how to get it.

All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

Offline

Yes, both of you are correct.

2) Let n and k be two positive integers such that k is less than n. It is know that (1+2+3+4+...+n)+k = 101. fFind k.

It's not how good you are. It's how good you want to be - Paul Arden

Offline

**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 81,656

Hi;

I have the result, but I do not yet know how to get it.

All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

Offline

Yes. Hmm...

3) Let 0 < y < 1. If A = y, B = y^2, C = 1/y and D = 1/y^2 arrange them from the largest to the smallest value.

How to do the message thing btw?

*Last edited by chooipian (2014-04-25 00:06:51)*

It's not how good you are. It's how good you want to be - Paul Arden

Offline

**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 81,656

Hi;

You mean a hide message?

I have the result, but I do not yet know how to get it.

All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

Offline

**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 81,656

Hi;

Use the hide tags.

and put what you want to hide between them. Yes I changed the order.

I have the result, but I do not yet know how to get it.

All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

Offline

4) Using only the numbers 1, 2, 3, 6, 7, 9, 0. Find which number goes with each of the letter in the addition problem below to make it correct. PAK = MAK = PIUT (I got this question for someone, I don't have a answer.)

5) Solve 200520062007^2 - 200520062006 x 200520062008 = (You are not allowed to use a calculator!)

That's all for now.

It's not how good you are. It's how good you want to be - Paul Arden

Offline

**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 81,656

Hi;

I have the result, but I do not yet know how to get it.

All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

Offline

Pages: **1**